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Tresset [83]
3 years ago
10

2. The radius of the larger circle is 5 meters. The radius of the smaller inde is 2.5 meters what is the approximate area of the

shaded region of the larger circle?
Mathematics
1 answer:
expeople1 [14]3 years ago
7 0

Answer:

c djc s s cs v f gs b sbfwbfyrfvrfurfvfpugwvpfwgvgcvw

Step-by-step explanation:

cvgvcuvucdcugbcubucvgevgvuvvcpgcgaw

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I need answer Immediately pls!!!!!!!
Anuta_ua [19.1K]

Answer:

1/14

Step-by-step explanation:

There is only 1 common multiple of 4 and 6 between 1 and 14.

So the probability is:

P = \frac{1}{14}

8 0
3 years ago
Read 2 more answers
Alexandra and Austin applied to the same university. They looked up the average SAT score of students admitted to that universit
Deffense [45]

Answer:

x= (y+40)-(y-330)

Step-by-step explanation:

According to the information provided, the difference in their scores would be the result of subtracting Austin's SAT score from Alexandra's SAT score.

Then, as Alexandra's SAT score was 40 points above the average score this means that you have to add 40 to the average score to get her result. Also, as Austin's SAT score was 330 points below the average score, this means that you have to subtract 330 from the average score. With this you can write the expression:

x= difference in their scores

y= average score

x= (y+40)-(y-330)

7 0
3 years ago
I thought of a number, added 4 5/7 to it, and got the number equal to the original one times 12. What was the original number?
Vilka [71]

Answer:

x=3/7

Step-by-step explanation:

x+4 5/7 = 12x

4 5/7 = 11x

x = 3/7

6 0
3 years ago
Read 2 more answers
What is the length of side s of the square shown below?
horsena [70]

Answer:

E

Explanation:

well, process of elimination

4 0
3 years ago
Read 2 more answers
Assume that you assign the following subjective probabilities for your final grade in your econometrics course (the standard GPA
rodikova [14]

Answer:

E(X) = 4*0.2 +3*0.5+ 2*0.2 +1*0.8+ 0*0.02= 2.78

So then the best answer for this case would be:

C. 2.78

Step-by-step explanation:

For this case we have the following probabability distribution function given:

Score         P(X)

A= 4.0       0.2

B= 3.0       0.5

C= 2.0       0.2

D= 1.0        0.08

F= 0.0       0.02

______________

Total          1.00

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

If we use the definition of expected value given by:

E(X) = \sum_{i=1}^n X_i P(X_I)

And if we replace the values that we have we got:

E(X) = 4*0.2 +3*0.5+ 2*0.2 +1*0.8+ 0*0.02= 2.78

So then the best answer for this case would be:

C. 2.78

3 0
3 years ago
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