The dP/dt of the adiabatic expansion is -42/11 kPa/min
<h3>How to calculate dP/dt in an adiabatic expansion?</h3>
An adiabatic process is a process in which there is no exchange of heat from the system to its surrounding neither during expansion nor during compression
Given b=1.5, P=7 kPa, V=110 cm³, and dV/dt=40 cm³/min
PVᵇ = C
Taking logs of both sides gives:
ln P + b ln V = ln C
Taking partial derivatives gives:

Substitutituting the values b, P, V and dV/dt into the derivative above:
1/7 x dP/dt + 1.5/110 x 40 = 0
1/7 x dP/dt + 6/11 = 0
1/7 x dP/dt = - 6/11
dP/dt = - 6/11 x 7
dP/dt = -42/11 kPa/min
Therefore, the value of dP/dt is -42/11 kPa/min
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Jo divided the rectangle into 4 parts if each part is 1/4 of the whole rectangle. 4 is the denominator which is the number of parts that has been divided.
Atmospheric pressure = 101,325 Newtons / m²
Weight per meter square = 101,325 Newtons
Mass per meter square = 101,325 / (9.81 x 1000)
Mass per meter square = 10.3 tonnes per m²
#5 is 96 because it is congruent to the one on top