By using the equations for <em>parabolic</em> motion, we proceed to present the answers for the paragraph seen in the picture: a) t ≈ 0.553 s, b) s = 2.212 m, c) s = 11.060 m.
<h3>How to analyze a system on parabolic motion</h3>
A system is on <em>parabolic</em> motion if such system can be represented as a particle, that is, a system whose geometry is negligible, and its motion is a combination of <em>horizontal</em> movement at <em>constant</em> velocity and <em>vertical</em> <em>uniformly accelerated</em> movement due to gravity and all <em>viscous</em> and <em>rotational</em> effects are negligible.
The time required for the droplet to reach the ground is:
1.5 m = (1 / 2) · (9.807 m / s²) · t²
t = √[2 · (1.5 m) / (9.807 m / s²)]
t ≈ 0.553 s
And the <em>horizontal</em> distance traveled by the droplet is:
s = (4 m / s) · (0.553 s)
s = 2.212 m
Now, we apply the same procedure for the case of sneezing person:
1.5 m = (1 / 2) · (9.807 m / s²) · t²
t = √[2 · (1.5 m) / (9.807 m / s²)]
t ≈ 0.553 s
s = (20 m / s) · (0.553 s)
s = 11.060 m
To learn more on parabolic motion: brainly.com/question/16992646
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Answer:
(a) The energy of the photon is 1.632 x 
J.
(b) The wavelength of the photon is 1.2 x 
m.
(c) The frequency of the photon is 2.47 x 
Hz.
Explanation:
Let;
= -13.60 ev
= -3.40 ev
(a) Energy of the emitted photon can be determined as;
- = -3.40 - (-13.60)
= -3.40 + 13.60
= 10.20 eV
= 10.20(1.6 x 
)
- = 1.632 x Joules
The energy of the emitted photon is 10.20 eV (or 1.632 x Joules).
(b) The wavelength, λ, can be determined as;
E = (hc)/ λ
where: E is the energy of the photon, h is the Planck's constant (6.6 x 
Js), c is the speed of light (3 x 
m/s) and λ is the wavelength.
10.20(1.6 x ) = (6.6 x * 3 x )/ λ
λ = 
= 1.213 x
Wavelength of the photon is 1.2 x m.
(c) The frequency can be determined by;
E = hf
where f is the frequency of the photon.
1.632 x = 6.6 x x f
f = 
= 2.47 x Hz
Frequency of the emitted photon is 2.47 x Hz.
