1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Scilla [17]
2 years ago
12

The diagram shows four paths from point A to point B.

Physics
1 answer:
iVinArrow [24]2 years ago
8 0
Path 2.

Displacement is the direction and magnitude of an object from its starting point, so path 2 is the direct route you would need to take to find direction and magnitude.
You might be interested in
Question 10 of 10
Alinara [238K]

it allows only a reduced number of electrons to flow through it.

4 0
3 years ago
Read 2 more answers
What does the principal quantum number determine?
morpeh [17]
<span>principal quantum number (n) </span>represents the relative overall energy of each orbital

Hope this helps!
4 0
2 years ago
Find the required angular speed, ω, of an ultracentrifuge for the radial acceleration of a point 1.80 cm from the axis to equal
Arturiano [62]

Answer:

The required angular speed ω of an ultra-centrifuge is:

ω = 18074 rad/sec

Explanation:

Given that:

Radius = r = 1.8 cm

Acceleration due to g = a = 6.0 x 10⁵ g

Sol:

We know that

Angular Acceleration = Angular Radius x Speed²

a = r x ω ²

Putting the values

6 x 10⁵ g = 1.8 cm x ω ²

Converting 1.8 cm to 0.018 m, also g = 9.8 ms⁻²

6 x 10⁵ x 9.8 = 0.018 x ω ²

ω ² = (6 x 10⁵ x 9.8) / 0.018

ω ² =  5880000 / 0.018

ω ² =  326666667

ω = 18074 rad/sec

7 0
3 years ago
you measured the torque caused by the gyroscope's weight by lifting up the end of the gyroscope (at 7.5 inches). If you measured
DIA [1.3K]

Answer:

i) No, the spring scale does not read a different value

ii) The torque will read a different value, it will reduce

iii) The spring scale does not need to be measured at the center of mass location.

Explanation:

The torque caused by the gyroscope can be given by the relation,

\tau = r × f

\tau = rf cos \theta

The torque measured by the gyroscope varies directly with the distance, r.

A decrease in the distance r will also cause a decrease in the value of the torque measured. When the distance, r is reduced from 7.5 inches to 5 inches, the torque caused by the gyroscope's weight also reduces.

The weight of the gyroscope remains constant despite the reduction in the distance because the weight  of the gyroscope is not a function of the distance from the gyroscope. Therefore, the spring scale will not read a different value.

Yes, the spring scale does not need to be measured from the center of mass location because the weight does not depend on the location of measurement. The reading of the sprig scale remains constant.

3 0
3 years ago
A redox reaction is always a single-displacement reaction, but a single-
Maurinko [17]
True, because it’s true
5 0
3 years ago
Other questions:
  • Least common shape for a galaxy is
    11·1 answer
  • Cassie lives two miles away from school. Which mode of transport could benefit her health? 
    10·2 answers
  • A constant force is exerted for a short time interval on a cart that is initially at rest on an air track. This force gives the
    9·1 answer
  • Which statement is true? *
    13·2 answers
  • The resistance of resistor is greater for:
    5·1 answer
  • A wave travels one complete cycle in20sec and has wavelength of 1000mm.what is the speed​
    8·1 answer
  • You are walking on a moving walkway in the airport. The length of the walkway is 59.1 m. If your velocity relative to the walkwa
    14·1 answer
  • A constant force of 12 N in the positive x direction acts on a 4.0-kg object as it moves from the origin to the point 6i-8j m. H
    5·1 answer
  • List two of the number of strategies you have learned
    10·1 answer
  • A vector is something with a magnitude and direction. Explain in 1 or 2 sentences the analogy between a vector and the voltage d
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!