Answer:
a) h = 14 m
b) h = 88 cm
c) f = 0.054 Hz
d) f = 0.13 Hz
Explanation:
a) T = 2π√(L/g)
L = T²g/4π²
L = (45/6)²(9.8) / 4π² = 13.963...
b) ½mv² = mgh
h = v²/2g
h = 4.15²/ (2(9.8)) = 0.87869
c) f = 1/T = 1 / (2π√(14 / 1.62)) = 0.0542
d) f = 6/45 = 0.13333...
Answer:
67000N
Explanation:
We solve for the acceleration using the the 3rd constant-acceleration equation.
(Vx)f² = (Vx)i² + 2ax∆x
We have the displacement to be
∆x = Xf - Xi = 940m
Vx = 70m/s
The acceleration = (70m/s)²/2(940m)
= 4900/1880
= 2.61m/s²
From isaac newton's second law,
51000kg x 2.61m/s²
= 133,000N
The engines thrust is half of this value
Therefore thrust = 67000N or 67kN
Referring to the attached image below which represents the complete rock cycle, we will find that a marble can be formed when hot magma is cooled and crystallized.
Applying this to the given diagram, we will find that marble is most likely formed in position
C
Answer with Explanation:
We are given that
Mass of superman=m=78 kg
Mass of train=m'=17863 kg
Speed of train=u'=75 km/h=

Let initial speed of superman=u
Momentum=mv
Using the formula



Average horizontal force=0.58
Deceleration 
Final speed of train=v'=0

Using the formula





Using the formula


