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Aleonysh [2.5K]
3 years ago
6

Definition of net force​

Physics
2 answers:
Lady bird [3.3K]3 years ago
4 0

Answer:

Net force is the vector sum of forces acting on a particle or body. The net force is a single force that replaces the effect of the original forces on the particle's motion. It gives the particle the same acceleration as all those actual forces together as described by Newton's second law of motion.

Explanation:

use this, but put it into you own words.

valentinak56 [21]3 years ago
3 0

Answer:

The vector sum of forces acting on a particle or body is referred to as net force. The net force is a single force that replaces the effect of the original forces on the motion of the particle. It provides the particle with the same acceleration as all of the actual forces combined, as described by Newton's second law of motion.

°•°•°•°•°•°•°•°•°•°•°•°•°•°•°•°•

Hope it helps

Have a great day!!

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Why can concave mirror is used in cosmetic mirror​
tatuchka [14]

Answer:

"When face is placed between the concave mirror and its focus, it produces a magnified image. This enlarged image of face is helpful in makeup as even pores of skin are clearly visible."

4 0
3 years ago
What is part of a line has one endpoint and continues in one direction?
noname [10]

Answer:

A Ray I believe since it sounds like it.

6 0
3 years ago
You push your little sister on a swing and in 1.1 minutes you make 54 pushes. what is the frequency of your swing? answer in uni
valentinak56 [21]
The frequency is the number of complete oscillations per second. One complete oscillation corresponds to 1 push. Converting the time into seconds:
t=1.1min \cdot 60 \frac{s}{min}=66 s
we can find the frequency of the swing:
f= \frac{54 pushes}{66 s}=0.81 Hz
3 0
3 years ago
A parallel combination of a 1.13-μF capacitor and a 2.85-μF one is connected in series to a 4.25-μF capacitor. This three-capaci
Nata [24]

Answer:

(a) Charge of 4.25 μF capacitor is 35.46 μC.

(b) Charge of 1.13 μF capacitor is 10.05 μC.

(c) Charge of 2.85 μF capacitor is 25.36 μC.

Explanation:

Let C₁ , C₂ and C₃ are the capacitor which are connected to the battery having voltage V. According to the problem, C₁ and C₂ are connected in parallel. There equivalent capacitance is:

C₄ = C₁ + C₂

Substitute 1.13 μF for C₁ and 2.85 μF for C₂ in the above equation.

C₄ = ( 1.13 + 2.85 ) μF = 3.98 μF

Since, C₄ and C₃ are connected in series, there equivalent capacitance is:

C₅ = \frac{C_{3}C_{4}  }{C_{3} + C_{4}  }

Substitute 4.25 μF for C₃ and 3.98 μF for C₄ in the above equation.

C₅ = \frac{4.25\times3.98 }{4.25 + 3.98  }

C₅ = 2.05 μF

The charge on the equivalent capacitance is determine by the relation :

Q = C₅ V

Substitute 2.05 μF for C₅ and 17.3 volts for V in the above equation.

Q = 2.05 μF x 17.3  = 35.46 μC

Since, the capacitors C₃ and C₄ are connected in series, so the charge on these capacitors are equal to the charge on the equivalent capacitor C₅.

Charge on the capacitor, C₃ = 35.46 μC

Charge on the capacitor, C₄ = 35.46 μC

Voltage on the capacitor C₄ = \frac{Q}{C_{4} } = \frac{35.46\times10^{-6} }{3.98\times10^{-6}} = 8.90 volts

Since, C₁ and C₂ are connected in parallel, the voltage drop on both the capacitors are same, that is equal to 8.90 volts.

Charge on the capacitor, C₁ = C₁ V = 1.13 μF x 8.90 = 10.05 μC

Charge on the capacitor, C₂ = C₂ V = 2.85 μF x 8.90 = 25.36 μC

5 0
3 years ago
you are traveling in a convertible with the top down. the car is moving at a constant velocty of 25 m/s due east along falt grou
velikii [3]

Answer:

Teh velocity of ball with respect to the ground is 29.2 m/s.

Explanation:

Velocity of car, vc = 25 due m/s east

velocity of ball with respect to car, v(b,c) = 15 m/s due Z axis

Write the velocities in the vector form

\overrightarrow{v}_{c}=25 \widehat{i}\\\\\overrightarrow{v}_{(b,c)}=15 \widehat{k}

The velocity of ball with respect to ground is

\overrightarrow{v}_{(b,c)}= \overrightarrow{v}_{(b,g)}-\overrightarrow{v}_{(c,g)}\\\\15 \widehat{k} = \overrightarrow{v}_{(b,g)} - 25 \widehat{i}\\\\\overrightarrow{v}_{(b,g)} = 25 \widehat{i} + 15 \widehat{k}\\\\v_{(b,g)}=\sqrt{25^2 + 15^2}=29.2 m/s

3 0
3 years ago
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