Help needed plz help

Mathematics

2 answers:

Aliun [14]3 years ago

6 0

Pretty sure the answer is C

KIM [24]3 years ago

4 0

The answer is x>3.5 for sure

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find the measure of the side of the right triangle whose length is designated by a lowercase letter. Round answers to the neares

mario62 [17]

Ah yes, math, I believe the answer you are looking for, my young scholar, is A

8 0

2 years ago

Please help me, thank you

Alenkinab [10]

Problem 1

Answer: C) No solution

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Explanation:

We have z = -4 and 4z = -4 at the same time. Solving 4z = -4 leads to z = -1

So in effect we have z = -4 and z = -1 at the same time, but this is a contradiction. A variable can only hold one number at a time.

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Problem 2

Answer: C) Infinitely many solutions

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Explanation:

The two equations are equivalent. You can prove as such by isolating 2y in the first equation.

5x = 8-2y

5x+2y = 8

2y = 8-5x

2y = -5x+8

-5x+8 = 2y

This shows the first equation is equivalent to the second, and vice versa. They both graph the same line. Any point along the line is a solution. So that's why there are infinitely many of them.

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Problem 3

Answer: Choice A) $-6 < y \le 3$

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Explanation:

The range is the set of the possible y values. We're concerned with every y coordinate of each (x,y) solution. So we only focus on the shaded region.

The dashed line means we exclude the boundary. It's an electric fence we cannot touch. So y > -6 or -6 < y describes part of the range

The other part is $y \le 3$ since y = 3 is the when the highest point occurs.

So writing $-6 < y \le 3$ describes all possible y values of each (x,y) solution in the shaded region.

6 0

3 years ago

Tan 2A + sin 2A=4 tan A/(1 - tan4 A)

stich3 [128]

Answer:

$when \: \\ \tan(2x) = \frac{2 \tan(x) }{1 - {( \tan(x)) }^{2} } \: \: and \\ \sin(2x) = \frac{2 \tan(x) }{1 + {( \tan(x)) }^{2} } \\ then \\ \sin(2x) + \tan(2x) = \frac{2 \tan(x) }{1 - {( \tan(x)) }^{2} } + \frac{2 \tan(x) }{1 + {( \tan(x)) }^{2} } \\ = \frac{2 \tan(x)(1 + {( \tan(x)) }^{2} + 2 \tan(x) (1 - {( \tan(x)) }^{2} }{(1 + {( \ \tan(x)) }^{2}(1 - {( \tan(x)) }^{2} } \\ = \frac{2 \tan(x) \times 2 }{1 - {( \tan(x) }^{4} } \\ = \frac{4 \tan(x) }{1 - {( \tan( \times ) )}^{4} }$