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Yuliya22 [10]
3 years ago
8

Help needed plz help

Mathematics
2 answers:
Aliun [14]3 years ago
6 0
Pretty sure the answer is C
KIM [24]3 years ago
4 0
The answer is x>3.5 for sure
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find the measure of the side of the right triangle whose length is designated by a lowercase letter. Round answers to the neares
mario62 [17]
Ah yes, math, I believe the answer you are looking for, my young scholar, is A
8 0
2 years ago
Please help me, thank you
Alenkinab [10]

Problem 1

Answer: C) No solution

---------------------------

Explanation:

We have z = -4 and 4z = -4 at the same time. Solving 4z = -4 leads to z = -1

So in effect we have z = -4 and z = -1 at the same time, but this is a contradiction. A variable can only hold one number at a time.

======================================================

Problem 2

Answer: C) Infinitely many solutions

---------------------------

Explanation:

The two equations are equivalent. You can prove as such by isolating 2y in the first equation.

5x = 8-2y

5x+2y = 8

2y = 8-5x

2y = -5x+8

-5x+8 = 2y

This shows the first equation is equivalent to the second, and vice versa. They both graph the same line. Any point along the line is a solution. So that's why there are infinitely many of them.

======================================================

Problem 3

Answer: Choice A) -6 < y \le 3

---------------------------

Explanation:

The range is the set of the possible y values. We're concerned with every y coordinate of each (x,y) solution. So we only focus on the shaded region.

The dashed line means we exclude the boundary. It's an electric fence we cannot touch. So y > -6 or -6 < y describes part of the range

The other part is y \le 3 since y = 3 is the when the highest point occurs.

So writing -6 < y \le 3 describes all possible y values of each (x,y) solution in the shaded region.

6 0
3 years ago
Tan 2A + sin 2A=4 tan A/(1 - tan4 A)​
stich3 [128]

Answer:

when \:  \\  \tan(2x)  =   \frac{2 \tan(x) }{1 -  {( \tan(x)) }^{2} }  \:  \: and \\  \sin(2x)  =  \frac{2 \tan(x) }{1 +  {( \tan(x)) }^{2} }  \\ then \\  \sin(2x)  +  \tan(2x)  =  \frac{2 \tan(x) }{1 -  {( \tan(x)) }^{2} }  +  \frac{2 \tan(x) }{1 +  {( \tan(x)) }^{2} }  \\  =  \frac{2 \tan(x)(1 +  {( \tan(x)) }^{2}  + 2 \tan(x) (1 -  {( \tan(x)) }^{2}  }{(1 +  {( \ \tan(x))  }^{2}(1 -  {( \tan(x)) }^{2}  }  \\  =  \frac{2 \tan(x) \times 2 }{1 -  {( \tan(x) }^{4} }  \\  =  \frac{4 \tan(x) }{1 -  {( \tan( \times ) )}^{4} }

Step-by-step explanation:

If you need any explanation. I can do it, my friend. you can communicate with me to that or any thing do you need in math

3 0
2 years ago
PLSSS HELP!!! ASAAPP
tia_tia [17]

Answer:

33/5 , or 16.5, or 16 1/2

Step-by-step explanation:

pemdas!

5 0
2 years ago
A non-repeating, non-terminating decimal is classified as?
harkovskaia [24]

Answer:

non-terminating/non-repeating

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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