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Gala2k [10]
3 years ago
10

Please answer! What is the scale factor from triangle a to triangle b? ​

Mathematics
2 answers:
Genrish500 [490]3 years ago
8 0
Triangle b is larger than triangle a
fgiga [73]3 years ago
8 0
Answer: The scale factor is 1.5

Explanation: The value of two corresponding legs are given. You use that and the knowledge of triangle A to B to create the equation 18/12. You then get the answer 1.5
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X2 + 4x -9 = (x + a)? +b<br> Find the value of a and the value of b.<br> a =<br> b=<br> ?
Burka [1]

Step-by-step explanation:

x² + 4x - 9

= (x + 2)² - 13

a = 2, b = -13.

4 0
3 years ago
A triangle has vertices (3,5), (5,2), and (2,0). Is the triangle a right triangle?
Artyom0805 [142]

Answer:

No, this is not a right triangle

Step-by-step explanation:

8 0
3 years ago
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Which expression is the additive inverse of n?<br> A. 1/n<br> B. -n<br> C. -1/n<br> D. -(-n)
Marrrta [24]
The additive inverse of something is whats added to the original to get 0

So in this case n - n = 0, which is B :)
6 0
3 years ago
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Find the point on the parabola y^2 = 4x that is closest to the point (2, 8).
guapka [62]

Answer:

(4, 4)

Step-by-step explanation:

There are a couple of ways to go at this:

  1. Write an expression for the distance from a point on the parabola to the given point, then differentiate that and set the derivative to zero.
  2. Find the equation of a normal line to the parabola that goes through the given point.

1. The distance formula tells us for some point (x, y) on the parabola, the distance d satisfies ...

... d² = (x -2)² +(y -8)² . . . . . . . the y in this equation is a function of x

Differentiating with respect to x and setting dd/dx=0, we have ...

... 2d(dd/dx) = 0 = 2(x -2) +2(y -8)(dy/dx)

We can factor 2 from this to get

... 0 = x -2 +(y -8)(dy/dx)

Differentiating the parabola's equation, we find ...

... 2y(dy/dx) = 4

... dy/dx = 2/y

Substituting for x (=y²/4) and dy/dx into our derivative equation above, we get

... 0 = y²/4 -2 +(y -8)(2/y) = y²/4 -16/y

... 64 = y³ . . . . . . multiply by 4y, add 64

... 4 = y . . . . . . . . cube root

... y²/4 = 16/4 = x = 4

_____

2. The derivative above tells us the slope at point (x, y) on the parabola is ...

... dy/dx = 2/y

Then the slope of the normal line at that point is ...

... -1/(dy/dx) = -y/2

The normal line through the point (2, 8) will have equation (in point-slope form) ...

... y - 8 = (-y/2)(x -2)

Substituting for x using the equation of the parabola, we get

... y - 8 = (-y/2)(y²/4 -2)

Multiplying by 8 gives ...

... 8y -64 = -y³ +8y

... y³ = 64 . . . . subtract 8y, multiply by -1

... y = 4 . . . . . . cube root

... x = y²/4 = 4

The point on the parabola that is closest to the point (2, 8) is (4, 4).

4 0
3 years ago
Find an<br> expression which represents the sum of (-X – 7) and (-9x + 6) in<br> simplest terms.
Strike441 [17]

Answer:

<u>sum</u><u> </u><u>is</u><u> </u><u>-</u><u>(</u><u>1</u><u>0</u><u>x</u><u> </u><u>+</u><u> </u><u>1</u><u>)</u>

Step-by-step explanation:

( - x - 7) + ( - 9x + 6) \\  = ( - x - 9x) + (6 - 7) \\  =  - 10x - 1 \\  =  - (10x + 1)

4 0
3 years ago
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