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Novosadov [1.4K]

3 years ago

10

What is the $25 fee Maria’s mother paid when Maria visited the doctor

2 answers:

Luba_88 [7]3 years ago

5 0

it is a co-insurance or an out-of-pocket expense

gayaneshka [121]3 years ago

4 0

The fee is known as a co pay.

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Probabilities with possible states of nature: s1, s2, and s3. Suppose that you are given a decision situation with three possibl

amm1812

Answer:

1. $P(s_1|I)=\frac{1}{11}$

2. $P(s_2|I)=\frac{8}{11}$

3. $P(s_3|I)=\frac{2}{11}$

Step-by-step explanation:

Given information:

$P(s_1)=0.1, P(s_2)=0.6, P(s_3)=0.3$

$P(I|s_1)=0.15,P(I|s_2)=0.2,P(I|s_3)=0.1$

(1)

We need to find the value of P(s₁|I).

$P(s_1|I)=\frac{P(I|s_1)P(s_1)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_1|I)=\frac{(0.15)(0.1)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_1|I)=\frac{0.015}{0.015+0.12+0.03}$

$P(s_1|I)=\frac{0.015}{0.165}$

$P(s_1|I)=\frac{1}{11}$

Therefore the value of P(s₁|I) is $\frac{1}{11}$ .

(2)

We need to find the value of P(s₂|I).

$P(s_2|I)=\frac{P(I|s_2)P(s_2)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_2|I)=\frac{(0.2)(0.6)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_2|I)=\frac{0.12}{0.015+0.12+0.03}$

$P(s_2|I)=\frac{0.12}{0.165}$

$P(s_2|I)=\frac{8}{11}$

Therefore the value of P(s₂|I) is $\frac{8}{11}$ .

(3)

We need to find the value of P(s₃|I).

$P(s_3|I)=\frac{P(I|s_3)P(s_3)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_3|I)=\frac{(0.1)(0.3)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_3|I)=\frac{0.03}{0.015+0.12+0.03}$

$P(s_3|I)=\frac{0.03}{0.165}$

$P(s_3|I)=\frac{2}{11}$

Therefore the value of P(s₃|I) is $\frac{2}{11}$ .

4 0

3 years ago

dimaraw [331]

32, i believe is the answer

5 0

3 years ago

Please help me with this question, image attached.

hichkok12 [17]

Answer:

corresponding angles

Step-by-step explanation:

<4 and <8 are corresponding angles

Corresponding angles are in matching corners on parallel lines

4 0

3 years ago

Read 2 more answers

How do I verify #15 using fundamental trig identities?

expeople1 [14]

We start with the more complicated side which is the left side, and show that, on using some trigonometric identities, we will get the term on the right side .

$\frac{sin \theta + tan \theta}{1+cos \theta}$

Using Quotient identity for tangent function, we will get

$\frac{sin \theta+ \frac{sin \theta}{cos \theta}}{1+cos \theta}$

$\frac{sin \theta cos \theta + sin \theta}{cos \theta(1+cos \theta)}$

Taking out sine function from the numerator

$=\frac{sin \theta(1+cos \theta)}{cos \theta(1+cos \theta)}$

Cancelling the common term of numerator and denominator

$=\frac{sin \theta}{cos \theta} = tan \theta$

7 0

3 years ago

The table represents a linear function.

Alona [7]

Answer: -6

See attached picture

6 0

3 years ago