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insens350 [35]
3 years ago
11

Did I do this equation correctly?​

Mathematics
1 answer:
Gre4nikov [31]3 years ago
3 0

Answer:

It looks correct!!!!!!!!!

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EXAMPLE 5 If f(x, y, z) = x sin(yz), (a) find the gradient of f and (b) find the directional derivative of f at (1, 2, 0) in the
solong [7]

Answer:

<h2>a) f =  sin(yz)i + xzcos(yz)j + xycos(yz)k</h2><h2>b) -2</h2>

Step-by-step explanation:

Given f(x, y, z) = x sin(yz), the formula for calculating the gradient of the function is expressed as ∇f(x, y, z) = fx(x, y, z)i+ fy(x, y, z)j+fz(x, y, z)k where;

fx, fy and fz are the differential of the functions with respect to x, y and z respectively.

a) ∇f(x, y, z) = sin(yz)i + xzcos(yz)j + xycos(yz)k

The gradient of f =  sin(yz)i + xzcos(yz)j + xycos(yz)k

b) Directional derivative of f at (1,2,0) in the direction of v = i + 4j − k is expressed as ∇f(1, 2, 0)*v

∇f(1, 2, 0) = sin(2(0))i +1*0cos(2*0)j + 1*2cos(2*0)k

∇f(1, 2, 0) = sin0i +0cos(0)j + 2cos(0)k

∇f(1, 2, 0) = 0i +0j + 2k

Given v = i + 4j − k

∇f(1, 2, 0)*v (note that this is the dot product of the two vectors)

∇f(1, 2, 0)*v =  (0i +0j + 2k)*(i + 4j − k )

Given i.i = j.j = k.k =1 and i.j=j.i=j.k=k.j=i.k = 0

∇f(1, 2, 0)*v = 0(i.i)+4*0(j.j)+2(-1)k.k

∇f(1, 2, 0)*v = 0(1)+0(1)-2(1)

∇f(1, 2, 0)*v =0+0-2

∇f(1, 2, 0)*v= -2

 

Hence, the directional derivative of f at (1, 2, 0) in the direction of v = i + 4j − k is -2

7 0
3 years ago
Um- help-.. please don’t comment if you don’t know
IRISSAK [1]

Answer:

Each point does NOT ALWAYS give the same amount of tickets.

11 point would most likely give 90 tickets.

Step-by-step explanation:

2 points give 18 tickets = 9 tickets per point

3 points give 27 tickets = 9 tickets per point

9 points give 72 tickets = 8 tickets per point

You can add the 2 point value with the 9 point values to find out many point it takes to get to 90 tickets.

18(2 tickets) + 72(9 tickets) = 90(11 tickets)

3 0
3 years ago
Read 2 more answers
The Department of Agriculture is monitoring the spread of mice by placing 100 mice at the start of the project. The population,
uranmaximum [27]

Answer:

Step-by-step explanation:

Assuming that the differential equation is

\frac{dP}{dt} = 0.04P\left(1-\frac{P}{500}\right).

We need to solve it and obtain an expression for P(t) in order to complete the exercise.

First of all, this is an example of the logistic equation, which has the general form

\frac{dP}{dt} = kP\left(1-\frac{P}{K}\right).

In order to make the calculation easier we are going to solve the general equation, and later substitute the values of the constants, notice that k=0.04 and K=500 and the initial condition P(0)=100.

Notice that this equation is separable, then

\frac{dP}{P(1-P/K)} = kdt.

Now, intagrating in both sides of the equation

\int\frac{dP}{P(1-P/K)} = \int kdt = kt +C.

In order to calculate the integral in the left hand side we make a partial fraction decomposition:

\frac{1}{P(1-P/K)} = \frac{1}{P} - \frac{1}{K-P}.

So,

\int\frac{dP}{P(1-P/K)} = \ln|P| - \ln|K-P| = \ln\left| \frac{P}{K-P} \right| = -\ln\left| \frac{K-P}{P} \right|.

We have obtained that:

-\ln\left| \frac{K-P}{P}\right| = kt +C

which is equivalent to

\ln\left| \frac{K-P}{P}\right|= -kt -C

Taking exponentials in both hands:

\left| \frac{K-P}{P}\right| = e^{-kt -C}

Hence,

\frac{K-P(t)}{P(t)} = Ae^{-kt}.

The next step is to substitute the given values in the statement of the problem:

\frac{500-P(t)}{P(t)} = Ae^{-0.04t}.

We calculate the value of A using the initial condition P(0)=100, substituting t=0:

\frac{500-100}{100} = A} and A=4.

So,

\frac{500-P(t)}{P(t)} = 4e^{-0.04t}.

Finally, as we want the value of t such that P(t)=200, we substitute this last value into the above equation. Thus,

\frac{500-200}{200} = 4e^{-0.04t}.

This is equivalent to \frac{3}{8} = e^{-0.04t}. Taking logarithms we get \ln\frac{3}{8} = -0.04t. Then,

t = \frac{\ln\frac{3}{8}}{-0.04} \approx 24.520731325.

So, the population of rats will be 200 after 25 months.

6 0
3 years ago
Three cube shaped boxes are stacked one above the other the volumes of two of the boxes are 1331 m³ each and the volume of the t
Pepsi [2]
So to find out the answer, you need to find out the dimensions of each cube. So for the 1331, it's 11 x 11 x 11. So you know that would be 11 meters high. Now the next cube. Then there's another 1331, so that would be another 11 meters high. Then 729, also 9 x 9 x 9, so that's going to be 9 meters high. Then add all the cube square roots. 11 + 11 + 9 = 31. So the height of the stacked boxes will be 31 meters.
5 0
3 years ago
What is the closed linear form for this sequence given a1 = 0.3 and an + 1 = an + 0.75?
german

Answer:

The closed linear form of the given sequence is a_{n}=0.75n-0.45

Step-by-step explanation:

Given that the first term a_{1}=0.3 and a_{n+1}=a_{n}+0.75

To find the closed linear form for the given sequence

The formula for arithmetic sequence is

a_{n}=a_{1}+(n - 1)d  (where d is the common difference)

The above equation is of the given form  a_{n+1}=a_{n}+0.75

Comparing this we get d=0.75

With a_{1}=0.3 and d=0.75

We can substitute these values in a_{n}=a_{1}+(n - 1)d

a_{n}=a_{1}+(n - 1)d

=0.3+(n-1)(0.75)

=0.3+0.75n-0.75

=-0.45+0.75n

Rewritting as below

=0.75n-0.45

Therefore a_{n}=0.75n-0.45

Therefore the closed linear form of the given sequence is a_{n}=0.75n-0.45

3 0
3 years ago
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