Constructing an a circle inscribed in a triangle involves these steps:
i) Draw 2 (or 3) of the angle bisectors. Their point of intersection is the center of the inscribed circle, or the incenter. Let's denote this point by O
ii) Draw a perpendicular line segment from the incenter to one of the sides. Let the intersection of the perpendicular from O and the side be T.
iii) Draw a circle with center the incenter, and radius the distance OT.
Answer: B) Only perpendicular bisectors are not involved.
let x x +2 x+4 three consecutive odd <span>integers
2x =9+ x+4 </span>Twice the smallest<span> is nine more than the largest
2x - x= 13
x= 13 the first
the second integer 15 the third 17 </span>
(-5)^2=25
25
-------------
-15 + - 5
25
------
-20
=-1.25
Answer:
Step-by-step explanation:
Given: f(x)=5x^3-51x^2+77x+100/x^2-11x+24
Please use parentheses to eliminate any ambiguity:
f(x) = (5x^3-51x^2+77x+100) / (x^2 - 11x + 24)
or (better yet):
5x^3-51x^2+77x+100
f(x) = ---------------------------------
x^2 - 11x + 24
The vertical asymptotes here are at the zeros of the denominator:
x^2 - 11x + 24 = 0, This quadratic equation has coefficients a = 1, b = -11 and c = 24. Thus, its roots (zeros) are:
-(-11) ± √( 121 - 4(1)(24) )
x = -------------------------------------
2(1)
or:
11 ± √( 25 )
x = --------------------
2
or: x = 8 and x = 3
The vertical asymptotes are x = 8 and x = 3.
If we attempt to divide x^2 - 11x + 24 into 5x^3 - 51x^2 + 77x + 100, we see that the first term of the quotient is 5x. As x increases or decreases without bound, 5x goes to either ∞ or -∞, so we conclude that there is no horiz. asymptote. Continuing this division results in:
5x + 4 + a fraction
This represents the slant asymptote, y = 5x + 4
Answer:
60º
Step-by-step explanation:
The interior angles of a triangle equals 180º. And 60+60+60=180, that is your answer.