Question

(×-5) second power equals 3​

Answer 1

Answer: $x_1=6.73\\\\x_2=3.26$

Step-by-step explanation:  

Given the following expression:

$(x-5)^2=3$

And knowing that:

$(a\±b)^2=a^2-2ab+b^2$

We get:

$x^2-2(x)(5)+5^2=3\\\\x^2-10x+25=3$

Move the 3 to the left side of the equation:

$x^2-10x+25-3=0\\\\x^2-10x+22=0$

Apply the Quadratic formula:

$x=\frac{-b\±\sqrt{b^2-4ac} }{2a}$

In this case:

$a=1\\b=-10\\c=22$

Substituting values into the Quadratic formula, we get:

$x=\frac{-(-10)\±\sqrt{(-10)^2-4(1)(22)} }{2(1)}\\\\\\x_1=6.73\\\\x_2=3.26$