Answer:
Draw a perpendicular line from point A to line segment BC. Name the intersection of said line at BC “E.” You now have a right angled triangle AED.
Now, you know AD = 6 m. Next, given that the trapezoid is a normal one, you know that the midpoints of AB and DC coincide. Therefore, you can find the length of DE like so, DE = (20–14)/2 = 3 m.
Next, we will use the cosign trigonometric function. We know, cos() = adjacent / hypotenuse. Hence, cosx = 3/6 = 1/2. Looking it up on a trigonometric table we know, cos(60 degrees) = 1/2. Therefore, x = 60 degrees.
Alternatively, you could simply use the Theorem for normal trapezoids that states that the base angles will be 60 degrees. Hope this helps!
The given equation is ⇒ y = -1.2 x + 24
<u>Part A : Graph the equation.</u>
To graph the equation, substitute with values of x then find y
The attached figure represents the table to graph the equation and the graph of the equation.
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<u>Part B : x-intercept</u>
To find x-intercept substitute with y = 0 and solve for x
∴ 0 = -1.2 x + 24
∴ 1.2 x = 24
∴ x = 24/1.2 = 20
x-intercept is at point (20,0)
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<u>Part C : y-intercept</u>
To find y-intercept substitute with x = 0 and solve for y
∴ y = -1.2 * 0 + 24
∴ y = 24
∴ y-intercept is at point (0,24)
Answer:
It will be the second one
Step-by-step explanation:
Hope this Helped
Answer: 2714.34m3
Step-by-step explanation:trust bra