$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$3000\\
r=rate\to 5.2\%\to \frac{5.2}{100}\to &0.052\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, thus four}
\end{array}\to &4\\
t=years\to &10
\end{cases}
\\\\\\
A=3000\left(1+\frac{0.052}{4}\right)^{4\cdot 10}\implies A=3000(1.013)^{40}
\\\\\\
A\approx 5029.201878874637$

7 0

3 years ago

Read 2 more answers

C) Parbati buys a mobile for Rs 6,300 and sells it to Laxmi at 15% profit. How much

Leni [432]

Answer:

Rs. 7245

Step-by-step explanation:

Given parameters:

Cost price = Rs. 6300

Percentage profit = 15%

Unknown:

Selling price = ?

Solution:

If profit is made on a trade, the selling price is higher than the cost price.

Profit = Selling price - Cost price

To find the selling price simply;

Selling price =( 1 + $\frac{15}{100}$ ) x cost price

Selling price = 1.15 x 6300 = Rs. 7245

6 0

3 years ago

Next in sequence 9/16, -9/8, 9/4, -9/2, 9, ?

pogonyaev

Answer:

-18

Step-by-step explanation:

*2, *(-2), *2, *(-2) ...

6 0

2 years ago