<span>Solving the equation for Y = 1.
5 * (3 * 1 - 2) = 15 * 1 - 10
5 * (3 - 2) = 15 -10
5 * 1 = 5
5 = 5
Solving the equation for Y = 2.
5 * (3 * 2 - 2) = 15 * 2 - 10
5 * (6 - 2) = 30 -10
5 * 4 = 20
20 = 20
Solving the equation for Y = 4.
5 * (3 * 4 - 2) = 15 * 4 - 10
5 * (12 - 2) = 60 -10
5 * 10 = 50
50 = 50
Solving the equation for Y = 8.
5 * (3 * 8 - 2) = 15 * 8 - 10
5 * (24 - 2) = 120 -10
5 * 22 = 110
110 = 110
Solving the equation for Y = 9.
5 * (3 * 9 - 2) = 15 * 9 - 10
5 * (27 - 2) = 135 -10
5 * 25 = 125
125 = 125
This proves that the equation holds good for at least 5 values of 'y', which are 1, 2, 4, 8 and 9.
However, it can be proved that the equation holds good for any value of y.
Expression 5(3y-2) can be simplified to 15y -10 which is the same expression on the right had side of the equation provided.
So, equation 5(3y-2)=15y-10 is actually 15y-10=15y-10 and since this is true for all values of y, it has been proved that it is true for at least 5 values of y.</span>
Answer:
The expected value of the game to the player is -$0.2105 and the expected loss if played the game 1000 times is -$210.5.
Step-by-step explanation:
Consider the provided information.
It is given that if ball lands on 29 players will get $140 otherwise casino will takes $4.
The probability of winning is 1/38. So, the probability of loss is 37/38.
Now, find the expected value of the game to the player as shown:
Hence, the expected value of the game to the player is -$0.2105.
Now find the expect to loss if played the game 1000 times.
1000×(-$0.2105)=-$210.5
Therefore, the expected loss if played the game 1000 times is -$210.5.
Answer:
A - 8x + 6x² + 2x
Step-by-step explanation:
source: trust me bro
