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victus00 [196]
3 years ago
5

A bar of metal is cooling from 1000°C to room temperature, 24°C. The temperature, H, of the bar t minutes after it starts coolin

g is given, in oc, by H = 24 + 976e-0.1t
(a) Find the temperature of the bar at the end of one hour. (Round your answer to the nearest degree.)
(b) Find the average value of the temperature over the first hour. (Round your answer to the nearest degree.)
(c) Is your answer to part (b) greater or smaller than the average of the temperatures at the beginning and the end of the hour? The answer to part (b) isecthan the average of the temperatures at the beginning and the end of the hour, because the graph is concave
Mathematics
1 answer:
motikmotik3 years ago
7 0

Answer:

ggfddv3=4

Step-by-step explanation:

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AnnZ [28]

Answer:

1. 13

2. 11

3. 10

4. 9

5. 12

6. 16

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8. 40

Step-by-step explanation:


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3 years ago
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blagie [28]

Answer:

Step-by-step explanation:

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4 0
3 years ago
A recipe calls for 5/8 cups butter. Angie wants to triple the recipe but she has only 1 1/4 cups of butter
Alisiya [41]
The recipe calls for 5/8 cups butter and Angie wants to triple the recipe.

Therefore, if Angie is tripling the recipe, she is multiplying all of the ingredients in the recipe by 3.

So for the butter, this would be:

5/8 * 3 = 15/8 

Next, we should turn this improper fraction into a mixed number so that we can compare it to the amount of butter that Angie has.

15/8 = 1 7/8 

1 7/8 > 1 1/4

Thus, Angie DOES NOT have enough butter to triple the recipe.
8 0
3 years ago
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Maru [420]

Step-by-step explanation:

<em>Combine like terms</em>

a. 2r + 3 + 4r = (2r + 4r) + 3 = 6r + 3

b. 8 + 3d + d = (3d + d) + 8 = 4d + 8

c. mn + (-3mn) + 6 = (mn - 3mn) + 6 = -2mn + 6

d. 10s + (-10) + (-4s) = (10s - 4s) - 10 = 14s - 10

<em>Terms are called "like terms" if they have the same variable part (the same letters in the same powers). Like terms differ at most coefficient.</em>

7 0
3 years ago
Solve for M.<br><br> 2G/k=5/M
BartSMP [9]

5k/2G is the answer to the problem.

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