The numbers are 105 and 50
<em><u>Solution:</u></em>
Let "x" be the first number
Let "y' be the second number
Twice a number plus twice a second number is 310
Therefore,
twice of x + twice of y = 310
2x + 2y = 310 ---------- eqn 1
The difference between the numbers is 55
x - y = 55 -------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
From eqn 2,
x = 55 + y ------ eqn 3
<em><u>Substitute eqn 3 in eqn 1</u></em>
2(55 + y) + 2y = 310
110 + 2y + 2y = 310
4y = 310 - 110
4y = 200
<h3>y = 50</h3>
<em><u>Substitute y = 50 in eqn 3</u></em>
x = 55 + 50
<h3>x = 105</h3>
Thus the numbers are 105 and 50
Answer:
(3x^2 + 2)(x + 4).
Step-by-step explanation:
3x3 + 12x2 + 2x + 8
3x^2(x + 4) + 2(x + 4) The x + 4 is common to the 2 groups so we have:
(3x^2 + 2)(x + 4).
Answer:
the distance is 4
Step-by-step explanation:
Answer:
200
Step-by-step explanation:
Answer:
130 degrees
Step-by-step explanation:
arc CA is 50 since the angle is 50 and then you would subtract from 180 since it is half the circle which leaves you with C, or 130 degrees.
