3 years ago

Can someone please help me on this please I beg you no links I really appreciate it plz

Mathematics

1 answer:

madam [21]3 years ago

3 0

Pretty sure you’re right!

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Find the area of the triangle with the given measurements. Round the solution to the nearest hundredth if necessary. B = 71°, a

mr_godi [17]

$\boxed{\text{Area of the triangle:} \dfrac{a \times c \times sin(\measuredangle B)}{2}} \\ \\ A = \dfrac{a \times c \times sin(\measuredangle B)}{2} \\ \\ A= \dfrac{11 \times 18 \times sin71 ^o }{2} \\ \\ \\ Note : sin 71^o \approx 0,94 \\ \\ \\ A = \dfrac{198 \times 0,94}{2} \\ \\ A= \dfrac{186.12}{2} \\ \\ A=93.6 \ cm^2$