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RUDIKE [14]
3 years ago
13

Numbers and letters in the alphabet - numbers of the months in the year

Mathematics
1 answer:
maxonik [38]3 years ago
8 0
So what exactly is your question
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What is the y-intercept of the line represented by the equation below?
allochka39001 [22]
B is the y intercept
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3 years ago
What is 2.475 as a fration in its lowest form?
Anon25 [30]
First you express it as a fraction so that would be 2475/1000 which can be simplified to 99/40






7 0
3 years ago
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I NEED HELPPPPPP It’s about constant rate I DONT GET THIS AT ALL :’( Explanation needed PLEASEEEEEEEE
Vika [28.1K]

Answer:

D Antenna #4

Step-by-step explanation:

As per given graph we can write the function

  • the intercept is zero, as x=0, y=0
  • at x=2, y=30  ⇒ 30= 2*15
  • at x=4, y=60 ⇒ 60= 4*15

The slope is 15, so the function is

  • y=15x

And the function for the antenna revolving at twice the rate would be

  • y=30x

Comparing data in given tables we can see it is D Antenna #4

  • x= 22 ⇒ y= 22*30= 660
  • x=24 ⇒ y= 24*30= 720
7 0
3 years ago
There are 210210210 students in a twelfth grade high school class. 909090 of these students have at least one sister and 1051051
BlackZzzverrR [31]

Answer:

(1) The value of P (A) is 0.4286.

(2) The value of P (B) is 0.50.

(3) The value of P (A ∩ B) is 0.2143.

(4) The the value of P (B|A) is 0.50.

(5) The events <em>A</em> and <em>B</em> are independent.

Step-by-step explanation:

The events are defined as follows:

<em>A</em> = a student in the class has a sister

<em>B</em> = a student has a brother

The information provided is:

<em>N</em> = 210

n (A) = 90

n (B) = 105

n (A ∩ B) = 45

The probability of an event <em>E</em> is the ratio of the favorable number of outcomes to the total number of outcomes.

P(E)=\frac{n(E)}{N}

The conditional probability of an event <em>X</em> provided that another event <em>Y</em> has already occurred is:

P(X|Y)=\frac{P(A\cap Y)}{P(Y)}

If the events <em>X</em> and <em>Y</em> are independent then,

P(X|Y)=P(X)

(1)

Compute the probability of event <em>A</em> as follows:

P(A)=\frac{n(A)}{N}\\\\=\frac{90}{210}\\\\=0.4286

The value of P (A) is 0.4286.

(2)

Compute the probability of event <em>B</em> as follows:

P(B)=\frac{n(B)}{N}\\\\=\frac{105}{210}\\\\=0.50

The value of P (B) is 0.50.

(3)

Compute the probability of event <em>A</em> and <em>B</em> as follows:

P(A\cap B)=\frac{n(A\cap B)}{N}\\\\=\frac{45}{210}\\\\=0.2143

The value of P (A ∩ B) is 0.2143.

(4)

Compute the probability of <em>B</em> given <em>A</em> as follows:

P(B|A)=\frac{P(A\cap B)}{P(A)}\\\\=\frac{0.2143}{0.4286}\\\\=0.50

The the value of P (B|A) is 0.50.

(5)

The value of P (B|A) = 0.50 = P (B).

Thus, the events <em>A</em> and <em>B</em> are independent.

6 0
3 years ago
Truth or Dare?<br> Have a nice day/night &lt;3
denpristay [2]

Answer:

Truth plz

Step-by-step explanation:

3 0
3 years ago
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