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3 years ago

Which equation has the steepest graph?

Mathematics

1 answer:

Alex17521 [72]3 years ago

5 0

A has the steepest graph because it has the highest gradient of 10.

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Please help practice Questions! will give thanks and star ratings (Question is attached)

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Pete has a 15-foot ladder. The safety instructions recommend he should have the base of the ladder 6 feet from the base of the w

AnnyKZ [126]

Answer:

tbh i think it equals 9

Step-by-step explanation:

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3 years ago

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A system of equations is shown below. y = –x – 3 5x + 2y = 9 What is the solution to this system?

erastovalidia [21]

Answer:

$x=5\ and\ y=-8$

The solution of the system can be given as (5,-8).

Step-by-step explanation:

Given system of equations:

$y=-x-3$

$5x+2y=9$

To solve the given system of equations:

Solution:

We will use substitution to solve the given system.

We will substitute the $y$ values in terms of $x$ from the equation $y=-x-3$ into the other equation to solve for $x$

Substituting $y=-x-3$ into $5x+2y=9$ .

We have:

$5x+2(-x-3)=9$

Using distribution.

$5x-2x-6=9$

Combining like terms.

$3x-6=9$

Adding 6 both sides.

$3x-6+6=9+6$

$3x=15$

Dividing both sides by 3.

$\frac{3x}{3}=\frac{15}{3}$

∴ $x=5$

Plugging in $x=5$ into $y=-x-3$ .

We have,

$y=-5-3$

∴ $y=-8$

The solution of the system can be given as (5,-8).

4 0

3 years ago

-4x/7>10 choose the solution set.

wolverine [178]

Answer:

I think it is c if not try to serch the answer up

3 0

3 years ago

Write each expression as an algebraic (nontrigonometric) expression in u, u > 0.

max2010maxim [7]

Answer:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0$

Step-by-step explanation:

We want to write the trignometric expression:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)\text{ where } u>0$

As an algebraic equation.

First, we can focus on the inner expression. Let θ equal the expression:

$\displaystyle \theta=\sec^{-1}\left(\frac{u}{10}\right)$

Take the secant of both sides:

$\displaystyle \sec(\theta)=\frac{u}{10}$

Since secant is the ratio of the hypotenuse side to the adjacent side, this means that the opposite side is:

$\displaystyle o=\sqrt{u^2-10^2}=\sqrt{u^2-100}$

By substitutition:

$\displaystyle= \sin(2\theta)$

Using an double-angle identity:

$=2\sin(\theta)\cos(\theta)$

We know that the opposite side is √(u² -100), the adjacent side is 10, and the hypotenuse is u. Therefore:

$\displaystyle =2\left(\frac{\sqrt{u^2-100}}{u}\right)\left(\frac{10}{u}\right)$

Simplify. Therefore:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0$

4 0

3 years ago