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11Alexandr11 [23.1K]
4 years ago
6

If a2= 18 and a4= 8, find two possible common ratios. Then, write two sequences lhaving five terms each.

Mathematics
1 answer:
Marizza181 [45]4 years ago
3 0

common ratio = a4/a3 = a3/a2

8/a3 = a3/18

(a3)^2 = 8 * 18

(a3)^2 = 144

a3 = 12 or a3 = -12

common ratio = 8/12 or common ratio = 8/(-12)

common ratio = 2/3 or common ratio = -2/3

Answer: 12 or -12

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Data on oxide thickness of semiconductors are as follows: 426, 433, 415, 420, 420, 438, 417, 410, 430, 434, 423, 426, 412, 434,
Luda [366]

Answer:

a) 423.458

b) 9.53

c) 1.94

d) 424.5

e) 0.2916

Step-by-step explanation:

We are given the following in the question:

426, 433, 415, 420, 420, 438, 417, 410, 430, 434, 423, 426, 412, 434, 435, 432, 409, 426, 409, 436, 422, 430, 411, 415

a) point estimate of the mean oxide thickness

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{10163}{24} = 423.458

b) point estimate of the standard deviation of oxide thickness

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Sum of squares of differences = 2089.958

s = \sqrt{\dfrac{2089.958}{23}} = 9.53

c) standard error of the point estimate

Standard error =

=\dfrac{\sigma}{\sqrt{n}} = \dfrac{9.53}{\sqrt{24}} = 1.94

d) point estimate of the median oxide thickness

Sorted data: 409, 409, 410, 411, 412, 415, 415, 417, 420, 420, 422, 423, 426, 426, 426, 430, 430, 432, 433, 434, 434, 435, 436, 438

Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}

Median =

\dfrac{12^{th}+13^{th}}{2} = \dfrac{423+426}{2} = 424.5

e) proportion of wafers in the population that have oxide thickness greater than 430 angstrom

Sample size, n = 24

Number of wafers with oxides greater than 430 angstrom, x = 7

p = \dfrac{x}{n} = \dfrac{7}{24} = 0.2916

7 0
4 years ago
Solve the equation or formula for the variable specified.<br> df+7h=5
Eva8 [605]
Please include the specified variable to solve for in this equation.
5 0
3 years ago
1.5.5 Practice: Modeling: Best Ticket Deal
posledela

The best ticket deal are illustrations of linear equations

The ticket system is a better deal to the max ticket

<h3>How to determine the best ticket deal</h3>

From the complete question, we have the following summary:

  • <u>Ticket System</u>

Charges = $22 per person

Surcharge = $10 per transaction

  • <u>Max Tickets</u>

Charges = $20 per person

Surcharge = $16 per transaction

Assume there would be only one transaction, the linear equations that represent the ticket deals are:

Ticket System: y = 22x + 10

Max Ticket: y = 20x + 16

The costs of ticket for two people in both deals are:

Ticket System: y = 22*2 + 10 = 54

Max Ticket: y = 20*2 + 16 = 56

By comparison;

54 is less than 56

This means that the ticket system is a better deal to the max ticket

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4 0
2 years ago
Find the value of n:<br> <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7B11%7D%20%3D%20%5Cfrac%7B3.5%7D%7B7%7D" id="TexFormul
EastWind [94]

The value of n from the given expression is 5.5

<h3>Solution to linear equation and fractions</h3>

Fractions are expression written as a ratio of two integers. The linear equation on the other hand has a leading degree of 1.

Given the equation below;

n/11 = 3.5/7

Simplify to have

n/11 = 1/2

Cross multiply the given result to have:

11 = 2n

Swap

2n = 11

Divide both sides by 2 to have;

2n/2 = 11/2

n = 5.5

Hence the value of n from the given expression is 5.5

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8 0
1 year ago
Can someone please help
victus00 [196]
The measure of angle 5 is also 111

Since angle 4 and angle 6 add up to equal 180, 180-111=69

angle 5 and angle 6 are also supplementary, so 180-69=again,111
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4 years ago
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