To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.
jk=ac and j+k=b
The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...
2k^2-5k-18=0
2k^2+4k-9k-18=0
2k(k+2)-9(k+2)=0
(2k-9)(k+2)=0
so k=-2 and 9/2
k=(-2, 4.5)
Answer:
6 29/40
Step-by-step explanation:
1/8 times 5 equals 5/40 and 3/5 times 8 equals 24/40 you add them together to get 29/40 which can not be simplified then add 4 and 2 to get 6 so <u>6 29/40 </u>is your answer.
Answer:
h= -7
hope this helps!!:)
Step-by-step explanation:
If the lines are congruent it should be 2 because 4 should be double of x
Answer:
20.8
Step-by-step explanation:
The first step you need to do is to subtract 11:
52.6 - 11 = 41.6
The second step is to divide it by 2:
41.6 / 2 = 20.8
Mark was thinking of 20.8
