Answer:
20:£1
Step-by-step explanation:
To simplify a ratio is like like simplifying a fraction
Take 4/8 as an example. Find a number you can divide both numbers with. In this case, it's 4. 4 divided by 4= 1, and 8 divided by 4= 2. So, the simplified version of 4/8 is 1/2. Similarly, with the ration 60:£3, you find the number you can divided both numbers with. In this case, it is 3. 3 divided by 3= 1, and 60 divided by 3= 20.
Final Answer: 20:£1
Remark
You don't have to decompose the second one, and it is better if you don't. Just find the area as you probably did: use the formula for a trapezoid. You have to assume that the 6cm line hits the 2 bases at right angles for each of them, otherwise, you don't know the height. So I'm going to assume that we are in agreement about the second one.
Problem One
The answer for this one has to be broken down and unfortunately, you answer is not right for the total area, although you might get 52 for the triangle. Let's check that out.
<em><u>Triangle</u></em>
Area = 1/2 * b * h
base = 16 cm
h = 10 - 4 = 6
Area = 1/2 * 16 * 6
Area = 48
<em><u>Area of the Rectangle</u></em>
Area = L * W
L = 16
W = 4
Area = L * W
Area = 16 * 4
Area = 64
<em><u>Total Area</u></em>
Area = 64 + 48
Area = 112 of both figures <<<< Answer
<span>4:12 or 1:3
20 character jump lol
kwapwao dpw</span>
The total would be $4.68. It is $0.78 for 0.4 of a pound, and you multiply $1.95 two times aqnd add that to the $0.78
The minimum value of a function is the place where the graph has a vertex at its lowest point.
There are two methods for determining the minimum value of a quadratic equation. Each of them can be useful in determining the minimum.
(1) By plotting graph
We can find the minimum value visually by graphing the equation and finding the minimum point on the graph. The y-value of the vertex of the graph will be the minimum.
(2) By solving equation
The second way to find the minimum value comes when we have the equation y = ax² + bx + c.
If our equation is in the form y = ax^2 + bx + c, you can find the minimum by using the equation min = c - b²/4a.
The first step is to determine whether your equation gives a maximum or minimum. This can be done by looking at the x² term.
If this term is positive, the vertex point will be a minimum; if it is negative, the vertex will be a maximum.
After determining that we actually will have a minimum point, use the equation to find it.
