<u>Corrected Question</u>
Suppose the value R(d) of d dollars in euros is given by
. The cost in dollars to purchase and ship n purses is given by P(n)=66n+23. Write a formula for the cost, Q(n) in euros to purchase and ship n purses.
Answer:

Step-by-step explanation:
The value R(d) of d dollars in euros is given by 
Therefore:


The cost P(n) in dollars to purchase and ship n purses is given by:

Therefore, the cost, Q(n) in euros to purchase and ship n purses

Answer:
Step-by-step explanation:
<u> 4 = 1 </u>
100 25
4 is the hundredths place, not hundreds because hundredths is a fraction of a whole. So its 4 over the value of its place which is 1 hundredths and 4 goes into itself 1 and 4 goes into 100, 25 times.
We know that 1 ton=2000 lbs
we have 2 tons=4,000 lbs
each crate holds 10 lbs of sugar
4,000/10=400 crates
Since (f/g)(x) = f(x)/g(x) for x to be in the domain of (f/g)(x) it must be in the domain of f and in the domain of g. You also need to insure that g(x) is not zero since f(x) is divided by g(x). Thus there are 3 conditions. x must be in the domain of f: f(x) = 3x -5 and all real numbers x are in the domain of x.
Given f(x) = 2x + 3 and g(x) = –x2 + 5, find ( f o f )(x).
( f o f )(x) = f ( f (x))
= f (2x + 3)
= 2( ) + 3 ... setting up to insert the input
= 2(2x + 3) + 3
= 4x + 6 + 3
= 4x + 9
Given f(x) = 2x + 3 and g(x) = –x2 + 5, find (g o g)(x).
(g o g)(x) = g(g(x))
= –( )2 + 5 ... setting up to insert the input
= –(–x2 + 5)2 + 5
= –(x4 – 10x2 + 25) + 5
= –x4 + 10x2 – 25 + 5
= –x4 + 10x2 – 20