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Irina18 [472]
3 years ago
12

What solid 3D object is produced by rotating the triangle about line m?

Mathematics
2 answers:
elena55 [62]3 years ago
6 0

Answer: A cone with height 3 and radius 1

Step-by-step explanation:

Hi, searching I found the image for the question, attached down below.

By rotating the triangle about line m, a cone with height 3 and radius 1 is produced.

Solid 3d objects are produced by rotating a 2d figure around a straight line that lies in the same place.

in our case, if we rotate the triangle around the line, the vertices in touch with the line m remains stationary, while the  remaining vertex follows the path of a circle, creating a cone.

Blizzard [7]3 years ago
4 0

Answer: A cone with height 3 units

Step-by-step explanation:

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ABCD is a Rhombus with side length 10 cm. Angle ADC = 40. DAC is a sector of a circle with center D. BAC is a sector of a circle
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The value of the <em>shaded</em> area is approximately 34.907 square centimeters.

<h3>How to calculate the area between a rhombus and a circle</h3>

According to the description in statement we prepared a representation of the figure in the image attached below. The <em>shaded</em> area is equal to the area of the <em>circle</em> sector (A), in square centimeters:

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Where:

  • R - Length of the radius, in centimeters.
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2 years ago
5. Mis the midpoint of CD. C has coordinates (-1,-1) and
lana66690 [7]

Answer/Step-by-step Explanation:

4. Midpoint (M) of AB, for A(-2, -3) and B(1, 2) is given as:

M(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})

Let A(-2, -3) = (x_1, y_1)

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5. Given M(3, 5) as midpoint of CD, and C(-1, -1),

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Rewrite the equation to find the coordinates of D

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Solve for each:

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6 = x_1 - 1

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5*2 = \frac{y_1 - 1}{2}*2

10 = y_1 - 1

10 + 1= y_1 - 1 + 1

11 = y_1

y_1 = 11

Coordinates of D is (7, 11)

7 0
3 years ago
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