Answer:
The maximum volume of the open box is 24.26 cm³
Step-by-step explanation:
The volume of the box is given as
, where
and
.
Expand the function to obtain:

Differentiate wrt x to obtain:

To find the point where the maximum value occurs, we solve



Discard x=3.54 because it is not within the given domain.
Apply the second derivative test to confirm the maximum critical point.
, 
This means the maximum volume occurs at
.
Substitute
into
to get the maximum volume.

The maximum volume of the open box is 24.26 cm³
See attachment for graph.
The answer should be J.15.
<span>If that line is parallel to one of the sides, then the statement is true.</span>
Answer:
value if a =

Step-by-step explanation:
here's the solution :-
=》
![\frac{ 2(\sqrt{m}) {}^{3} }{ \sqrt[4]{m} }](https://tex.z-dn.net/?f=%20%5Cfrac%7B%202%28%5Csqrt%7Bm%7D%29%20%20%7B%7D%5E%7B3%7D%20%7D%7B%20%5Csqrt%5B4%5D%7Bm%7D%20%7D%20)
=》

=》

=》

=》

=》

so, a = 5/4
The answer is 112.09 i added 89+3+3+8+2=105+7.09=112.09