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nlexa [21]
2 years ago
13

(a) The diagram below, not drawn to scale, shows a circle, centre 0. EH and EF are tangents to the circle. FOG and JOH are strai

ght lines. The measure of ZFCH = 44º. 44° Calculate, giving reasons for your answer, the measure of: (i) ZEHF (ii) ZFGH (2 marks) (2 marks) (iii)JHE (2 marks (iv) ZJGH 90 (2 marks)​
Mathematics
1 answer:
posledela2 years ago
6 0

Answer:

it is 6574 for the math problem

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Start at the given point. Draw a segment from that point through the center of the circle, and extend the segment until it intersects the circle. The new point of intersection of the segment and the circle is the image of the original point.
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Express as a sum: x–y–z<br><br> plz help i will give branilly for the correct answer
babymother [125]

Answer:

i am positive it is x+y+z

Step-by-step explanation:

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3 0
3 years ago
Find the angle θ between u = &lt;7, –2&gt; and v = &lt;–1, 2&gt;.
Dmitry_Shevchenko [17]

The angle between two vectors is:

CosФ = u - v / Magnitude(u) x magnitude(v)

Magnitude of u = SQRT(7^2 + -2^2) = SQRT(49 +4) = SQRT(53)

Magnitude of v = SQRT(-1^2 +2^2) = SQRT(1 +4) = SQRT(5)

u x v = (7 x -1) + (-2 x 2) = -7 + -4 = -11

cosФ = -11 / sqrt(53) x sqrt(5)

cosФ = -11sqrt265) / 265

Ф =cos^-1(-11sqrt265) / 265)

Ф=132.51 degrees.

7 0
3 years ago
Read 2 more answers
Find the angle between the given vectors to the nearest tenth of a degree. u = , v = (2 points)
Liono4ka [1.6K]

Answer:

<h2>3.6°</h2>

Step-by-step explanation:

The question is incomplete. Here is the complete question.

Find the angle between the given vectors to the nearest tenth of a degree.

u = <8, 7>, v = <9, 7>

we will be using the formula below to calculate the angle between the two vectors;

u*v = |u||v| cos \theta

\theta is the angle between the two vectors.

u = 8i + 7j and v = 9i+7j

u*v = (8i + 7j )*(9i + 7j )

u*v = 8(9) + 7(7)

u*v = 72+49

u*v = 121

|u| = √8²+7²

|u| = √64+49

|u| = √113

|v| = √9²+7²

|v| = √81+49

|v| = √130

Substituting the values into the formula;

121= √113*√130 cos θ

cos θ = 121/121.20

cos θ = 0.998

θ = cos⁻¹0.998

θ = 3.6° (to nearest tenth)

Hence, the angle between the given vectors is 3.6°

5 0
3 years ago
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MrRa [10]

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Step-by-step explanation:

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