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marta [7]
3 years ago
14

GC = 4x + 5, CF = 3x – 2, and GF = 24. What is the value of x?

Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
6 0
G = F(4x+5)/ 3x-2
C = (4x+5) (3x-2)/ 24C
F = 3x-2/C
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Three times the sum of a number and seven is negative thirty-six. What is the number?
Katarina [22]

Answer:

n =-19

Step-by-step explanation:

3* (n+7) = -36

Distribute

3n+21 = -36

Subtract 21 from each side

3n+21-21 = -36-21

3n = -57

Divide by 3

3n/3 = -57/3

n =-19

7 0
3 years ago
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Write the expanded form for 34.75
S_A_V [24]

Answer:

30+4+0.7+0.05

Step-by-step explanation:

Because the expanded form is added the number.

3=30

4=4.

7=0.7

and 5=0.05 so all together is 30+4+0.7+0.05

7 0
2 years ago
What’s 4x + 7y + 4 + 5x + y
fomenos

Hello!

Okay, so first we need to add like terms... so first, add the terms with the same variables. That gives us:

9x + 7y + 4 + y

Now add 7y and y

That gives us:

9x + 8y + 4

This can't be added anymore... this is as far as we can go because they are no longer like terms.

6 0
3 years ago
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How to do divisibility tables
zhannawk [14.2K]
What's a divisability table are you. B or a g how old
3 0
3 years ago
For the given hypothesis test, determine the probability of a Type II error or the power, as specified. A hypothesis test is to
erica [24]

Answer:

the probability of a Type II error if in fact the mean waiting time u, is 9.8 minutes is 0.1251

Option A) is the correct answer.

Step-by-step explanation:

Given the data in the question;

we know that a type 11 error occur when a null hypothesis is false and we fail to reject it.

as in it in the question;

obtained mean is 9.8 which is obviously not equal to 8.3

But still we fail to reject the null hypothesis says mean is 8.3

Hence we have to find the probability of type 11 error

given that; it is right tailed and o.5, it corresponds to 1.645

so

z is equal to 1.645

z = (x-μ)/\frac{S}{\sqrt{n} }

where our standard deviation s = 3.8

sample size n = 50

mean μ = 8.3

we substitute

1.645 = (x - 8.3)/\frac{3.8}{\sqrt{50} }

1.645 = (x - 8.3) / 0.5374

0.884023 = x - 8.3

x = 0.884023 + 8.3

x = 9.18402

so, by general rule we will fail to reject the null hypothesis when we will get the z value less than 1.645

As we reject the null hypothesis for right tailed test when the obtained test statistics is greater than the critical value

so, we will fail to reject the null hypothesis as long as we get the sample mean less than 9.18402

Now, for mean 9.8 and standard deviation 3.8 and sample size 50

Z =  (9.18402 - 9.8)/\frac{3.8}{\sqrt{50} }

Z = -0.61598 / 0.5374

Z = - 1.1462 ≈ - 1.15

from the z-score table;

P(z<-1.15) = 0.1251

Therefore, the probability of a Type II error if in fact the mean waiting time u, is 9.8 minutes is 0.1251

Option A) is the correct answer.

8 0
3 years ago
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