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marta [7]
3 years ago
14

GC = 4x + 5, CF = 3x – 2, and GF = 24. What is the value of x?

Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
6 0
G = F(4x+5)/ 3x-2
C = (4x+5) (3x-2)/ 24C
F = 3x-2/C
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How do you find the area of this
zlopas [31]

Answer:

2345 units^2

Step-by-step explanation:

First, you can use Soh Cah Toa to find line c to be 36*sqrt(2). Furthermore, you can use the same equation to find the other sides to be both 65.15. To further solve, you just need to multiply 65.15 by 36 to get a final answer of 2,345.4 units^2

<em>Please Mark Brainliest if this helped!</em>

5 0
3 years ago
4) The path of a satellite orbiting the earth causes it to pass directly over two
Naily [24]

Answers:

  • Satellite is approximately <u>2446.43 km</u> from station A.
  • Satellite is approximately <u>2441.61 km</u> above the ground.

=========================================================

Explanation:

I'm assuming tracking stations A and B are at the same elevation and are on flat ground. In reality, this is likely not the case; however, for the sake of simplicity, we'll assume this is the case.

The diagram is shown below. Points A and B describe the two stations, while point C is the satellite's location. Point D is on the ground directly below the satellite. We have these lengths

  • AB = 60 km
  • AD = x
  • CD = h

Focusing on triangle ACD, we can apply the tangent rule to isolate h.

tan(angle) = opposite/adjacent

tan(A) = CD/AD

tan(86.4) = h/x

x*tan(86.4) = h

h = x*tan(86.4)

We'll use this later in the substitution below.

--------------------

Now move onto triangle BCD. For the reference angle B = 85, we can use the tangent rule to say

tan(angle) = opposite/adjacent

tan(B) = CD/DB

tan(B) = CD/(DA+AB)

tan(85) = h/(x+60)

tan(85)*(x+60) = h

tan(85)*(x+60) = x*tan(86.4) .............  apply substitution; isolate x

x*tan(85)+60*tan(85) = x*tan(86.4)

60*tan(85) = x*tan(86.4)-x*tan(85)

60*tan(85) = x*(tan(86.4)-tan(85))

x*(tan(86.4)-tan(85)) = 60*tan(85)

x = 60*tan(85)/(tan(86.4)-tan(85))

x = 153.612786190499

--------------------

We'll use this approximate x value to find h

h = x*tan(86.4)

h = 153.612786190499*tan(86.4)

h = 2441.60531869599

h = 2441.61 km  is how high the satellite is above the ground.

Return to triangle ACD. We'll use the cosine rule to determine the length of the hypotenuse AC

cos(angle) = adjacent/hypotenuse

cos(A) = AD/AC

cos(86.4) = x/AC

cos(86.4) = 153.612786190499/AC

AC*cos(86.4) = 153.612786190499

AC = 153.612786190499/cos(86.4)

AC = 2446.43279498247

AC = 2446.43 km is the distance from the satellite to station A.

6 0
3 years ago
John saves N$ 4225 the first month and every month later decreases it by N$ 65. How much will much John save in the 13th month?
castortr0y [4]

Answer:

nadaa

Step-by-step explanation:

4 0
3 years ago
A farmer has a field in the shape of a semicircle of diameter 50 m. First,
dexar [7]

Answer:

157.1 m

Step-by-step explanation:

Here, we want to calculate the length of the semi-circle

This simply refers to the circumference of the semi-circle

Mathematically, the circumference is half that of a full circle

The circumference of a full circle is;

C = pi * d

For half circle or semi-circle;

It is ;

C = (pi * d)/2

D = 50 m

The circumference is thus;

C = 50 * 3.142

C = 157.1 m

5 0
3 years ago
Find the ninth term of the sequence sqrt 5, sqrt 10, ^2sqrt 5
hjlf
The rule of geometric sequence is   ⇒⇒⇒ a * r^(n-1)
Where a is the first term and  r is the common ratio
for the given sequence  √5 , √10 , 2√5 , .......
a = √5
r = √10 / √5 = √2
The ninth term = √5 * (√2)^(9-1) = √5 * (√2)⁸ = 16 √5

the correct answer is the third option 16√5
5 0
3 years ago
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