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2 years ago

F(x)=1/2(x-2)(x+3)^3

Mathematics

1 answer:

KatRina [158]2 years ago

5 0

Answer:y=

x4+

x3+

x2+

−27

x−27

Step-by-step explanation:

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The figure below shows square ABCD inscribed on square PQRM on a coordinate plane. Which of the following expressions represents

vova2212 [387]

The hypotenuse of the triangle is given by:
$CB ^ 2 = RC ^ 2 + RB ^ 2
$
Substituting values:
$CB ^ 2 = 2 ^ 2 + 4 ^ 2
$
Clearing CB we have:
$CB = \sqrt{ 2 ^ 2 + 4 ^ 2} 

 CB = \sqrt{ 4 + 16} 

 CB = \sqrt{20} 

 CB = \sqrt{4*5} 

 CB = 2\sqrt{5} 



$
Then, the perimeter of the triangle is:
$P = RB + RC + CB
$
Substituting values:
$P = 4 + 2 + 2 \sqrt{5} 

 P = 6 + 2 \sqrt{5}$
Answer:
the perimeter of triangle BRC in units is:
D.6 + 2√5

7 0

2 years ago

Read 2 more answers

Please help me with this

masha68 [24]

Answer:

Step-by-step explanation:

10x-11+3x-2+3x+1=180

16x-12=180

16x=192

x=12

7 0

2 years ago

Read 2 more answers

-3/8x - 11 = 4 pls HELP me im getting no where right now.

VashaNatasha [74]

-3/8x - 11 = 4
-3/8x = 15 Add 11 to both sides
x = -40 Divide both sides by -3/8

7 0

3 years ago

Help me againnnnnnnnnnnnnnnnnnnnnnn

OLEGan [10]

Step-by-step explanation:

(2m + 4) / 8 = w

2m + 4 = 8w

2m = 8w - 4

m = 4w - 2

8 0

2 years ago

Read 2 more answers

Shortern this expression pls

pogonyaev

Answer:

$c =\frac{8}{3}$

Step-by-step explanation:

Given

$c = \sqrt{\frac{4 + \sqrt 7}{4 - \sqrt 7}} + \sqrt{\frac{4 - \sqrt 7}{4 + \sqrt 7}}$

Required

Shorten

We have:

$c = \sqrt{\frac{4 + \sqrt 7}{4 - \sqrt 7}} + \sqrt{\frac{4 - \sqrt 7}{4 + \sqrt 7}}$

Rationalize

$c = \sqrt{\frac{4 + \sqrt 7}{4 - \sqrt 7} * \frac{4 + \sqrt 7}{4 + \sqrt 7}} + \sqrt{\frac{4 - \sqrt 7}{4 + \sqrt 7}*\frac{4 - \sqrt 7}{4 - \sqrt 7}}$