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4 years ago

11

A bag contains 56 marbles ,some red ,some yellow ,some blue,there are half as many red as blue and eight more yellow than red .h

ow many of each color are there?

1 answer:

Delicious77 [7]4 years ago

7 0

Let red marbles be x.

Blue : 2x
Red : x
Yellow : x+8

2x + x + x + 8 = 56
4x = 48
x = 12

Red marbles: 12
Blue : 24
Yellow: 20

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Explain your answer !! <br> Have a nice day <br><br> Will give braisnlt

SashulF [63]

Answer:

The equations are:

$4H + 3P = 13.75$

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Step-by-step explanation:

Let:

$H = hot\ dog$

$P =Pretzel$

For Tina:

$4H + 3P = 13.75$

For Doug:

$2H + 5P = 11.25$

Solving for the price of both items:

We have:

$4H + 3P = 13.75$ --- (1)

$2H + 5P = 11.25$ --- (2)

Multiply (2) by 2

2 * ( $2H + 5P = 11.25$ )

-------------------

$4H + 10P = 22.50$ --- (3)

Subtract (3) from (1)

$4H + 3P = 13.75$

$4H + 10P = 22.50$

----------------------

$4H - 4H + 3P - 10P = 13.75 - 22.50$

$3P - 10P = 13.75 - 22.50$

$-7P = -8.75$

Solve for P

$P = \frac{-8.75}{-7}$

$P = 1.25$

Substitute 1.25 for P in (2)

$2H + 5P = 11.25$

$2H + 5 * 1.25 = 11.25$

$2H + 6.25 = 11.25$

Collect Like Terms

$2H = 11.25-6.25$

$2H = 5$

Solve for H

$H = \frac{5}{2}$

$H = 2.50$

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