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3 years ago

5x - 7 = 5 - x show work please

Mathematics

1 answer:

liberstina [14]3 years ago

5 0

Answer:

x=2

Step-by-step explanation:

5x-7=5-x

5x=12-x

6x=12

x=2

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Test the null hypothesis Upper H 0 : (mu 1 minus mu 2 )equals 0H0: μ1−μ2=0 versus the alternative hypothesis Upper H Subscript a

Law Incorporation [45]

Answer:

The test statistic t is t=2.9037.

The null hypothesis is rejected.

For a significance level of 0.05, there is enough evidence to support the alternative hypothesis.

Step-by-step explanation:

The question is incomplete:

The sample 1, of size n1=25 has a mean of 1.15 and a standard deviation of 0.31.

The sample 2, of size n2=25 has a mean of 0.95 and a standard deviation of 0.15.

This is a hypothesis test for the difference between populations means.

The null and alternative hypothesis are:

$H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2\neq 0$

The significance level is α=0.05.

The difference between sample means is Md=0.2.

$M_d=M_1-M_2=1.15-0.95=0.2$

The estimated standard error of the difference between means is computed using the formula:

$s_{M_d}=\sqrt{\dfrac{\sigma_1^2+\sigma_2^2}{n}}=\sqrt{\dfrac{0.31^2+0.15^2}{25}}\\\\\\s_{M_d}=\sqrt{\dfrac{0.119}{25}}=\sqrt{0.005}=0.069$

Then, we can calculate the t-statistic as:

$t=\dfrac{M_d-(\mu_1-\mu_2)}{s_{M_d}}=\dfrac{0.2-0}{0.069}=\dfrac{0.2}{0.069}=2.9037$

The degrees of freedom for this test are:

$df=n_1+n_2-1=25+25-2=48$

This test is a two-tailed test, with 48 degrees of freedom and t=2.9037, so the P-value for this test is calculated as (using a t-table):

$P-value=2\cdot P(t>2.9037)=0.0056$

As the P-value (0.0056) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

8 0

3 years ago

Help someone!! Thank you!

Margaret [11]

Answer:

D. 1.3

Step-by-step explanation:

Perimeter (square) = 4*side

4 = 4*side

side = 1

We have triangle QVR. QV is a hypotenuse.

If we look at the triangle QTR, QT is a hypotenuse.

QV should be less than QT.

Let's find QT using Pythagorean theorem.

c² = a² + b²

QT² = QR² + RT² = 1² + 1² = 2

QT = √2 ≈ 1.4

QV < QT

QV < 1.4

We have 1.3 and 1 that are less than 1.4, but 1 is a length of a leg of the triangle, so 1 is impossible.

Answer D. 1.3

4 0

3 years ago

Read 2 more answers

Someone please help me

pshichka [43]

That is C and B. The missing lengths

3 0

3 years ago

\The lengths of a lawn mower part are approximately normally distributed with a given mean Mu = 4 in. and standard deviation Sig

chubhunter [2.5K]

Answer:

68.26% of the parts will have lengths between 3.8 in. and 4.2 in.

Step-by-step explanation:

The lengths of a lawn mower part are approximately normally distributed

$\mu = 4$

Standard deviation = $\sigma =0.2$

We are supposed to find What percentage of the parts will have lengths between 3.8 in. and 4.2 in . i.e. P(3.8<x<4.2)

Formula : $Z=\frac{x-\mu}{\sigma}$

At x = 3.8

$Z=\frac{3.8-4}{0.2}$

Z=-1

Refer the z table for p value

p value =0.1587

At x =4.2

$Z=\frac{4.2-4}{0.2}$

Z=1

Refer the z table for p value

p value =0.8413

P(3.8<x<4.2)=P(x<4.2)-P(x<3.8)=0.8413-0.1587=0.6826

So, 68.26% of the parts will have lengths between 3.8 in. and 4.2 in.

3 0

4 years ago

The value of 4 less than the product of 0.25 and x is greater than 6.

ella [17]

Answer:

0.25x - 4 > 6

7 0

3 years ago