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lesantik [10]
3 years ago
9

5x - 7 = 5 - x show work please

Mathematics
1 answer:
liberstina [14]3 years ago
5 0

Answer:

x=2

Step-by-step explanation:

5x-7=5-x

5x=12-x

6x=12

x=2

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3 years ago
Read 2 more answers
Given:
diamong [38]

Answer:

10-5\sqrt{2}

Step-by-step explanation:

As per the attached figure, right angled \triangle MDL has an inscribed circle whose center is I.

We have joined the incenter I to the vertices of the \triangle MDL.

Sides MD and DL are equal because we are given that \angle M = \angle L = 45 ^\circ.

Formula for <em>area</em> of a \triangle = \dfrac{1}{2} \times base \times height

As per the figure attached, we are given that side <em>a = 10.</em>

Using pythagoras theorem, we can easily calculate that side ML = 10\sqrt{2}

Points P,Q and R are at 90 ^\circ on the sides ML, MD and DL respectively so IQ, IR and IP are heights of  \triangleMIL, \triangleMID and \triangleDIL.

Also,

\text {Area of } \triangle MDL = \text {Area of } \triangle MIL +\text {Area of } \triangle MID+ \text {Area of } \triangle DIL

\dfrac{1}{2} \times 10 \times 10 = \dfrac{1}{2} \times r \times 10 + \dfrac{1}{2} \times r \times 10 + \dfrac{1}{2} \times r \times 10\sqrt2\\\Rightarrow r = \dfrac {10}{2+\sqrt2} \\\Rightarrow r = \dfrac{5\sqrt2}{\sqrt2+1}\\\text{Multiplying and divinding by }(\sqrt2 +1)\\\Rightarrow r = 10-5\sqrt2

So, radius of circle = 10-5\sqrt2

8 0
3 years ago
The diagram shows the ratio of trees Maeve plants to the trees she harvests.
AnnZ [28]

Answer:

WEDNESDAY: 45 planted.

THURSDAY: 22 Harvested.

Step-by-step explanation:

Based on the information given in the problem, Maeve plants 5 trees for every 2 tree she harvests. Then the ratio can be expressed as following:

5:2 or \frac{5}{2}

Then, you can complete the values in the table as you can see below:

<u>WEDNESDAY</u>

\frac{5}{2}=\frac{planted}{18}\\\\planted=\frac{18*5}{2}\\\\planted=45

<u>THURDAY</u>

\frac{5}{2}=\frac{55}{harvested}\\\\(harvested)(\frac{5}{2})=55\\\\harvested=\frac{55*2}{5}\\\\harvested=22

6 0
3 years ago
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