3 years ago

a 5L solution was 21% vinegar was mixed with a 13L solution that was 60% vinegar. find the new concentration of vinegar.

Mathematics

1 answer:

Iteru [2.4K]3 years ago

6 0

Let the concentration of new vinegar solution is x%.

According to question, we will get

$0.21*5 +0.6*13 = 0.0x*(5+13)$

$1.05 +7.8 = 0.18x$

$8.85 = 0.18x
\\
x = 49.17$

Therefore the new concentration of vinegar is 49.17% .

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