a 5L solution was 21% vinegar was mixed with a 13L solution that was 60% vinegar. find the new concentration of vinegar.
1 answer:
Let the concentration of new vinegar solution is x%.
According to question, we will get
![0.21*5 +0.6*13 = 0.0x*(5+13)](https://tex.z-dn.net/?f=0.21%2A5%20%2B0.6%2A13%20%3D%200.0x%2A%285%2B13%29)
![1.05 +7.8 = 0.18x](https://tex.z-dn.net/?f=1.05%20%2B7.8%20%3D%200.18x)
![8.85 = 0.18x \\ x = 49.17](https://tex.z-dn.net/?f=8.85%20%3D%200.18x%0A%5C%5C%0Ax%20%3D%2049.17)
Therefore the new concentration of vinegar is 49.17% .
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