Question

a 5L solution was 21% vinegar was mixed with a 13L solution that was 60% vinegar. find the new concentration of vinegar.

Answer 1

Let the concentration of new vinegar solution is x%.

According to question, we will get

$0.21*5 +0.6*13 = 0.0x*(5+13)$

$1.05 +7.8 = 0.18x$

$8.85 = 0.18x \\ x = 49.17$

Therefore the new concentration of vinegar is 49.17% .