Answer:
The 98% confidence interval estimate of the true average amount of soft drink in each bottle is between 2.97 liters and 3.01 liters.
Step-by-step explanation:
We have the standard deviation for the sample, so we use the t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 64 - 1 = 63
98% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 63 degrees of freedom(y-axis) and a confidence level of
. So we have T = 2.387
The margin of error is:

In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 2.99 - 0.02 = 2.97 liters
The upper end of the interval is the sample mean added to M. So it is 2.99 + 0.02 = 3.01 liters
The 98% confidence interval estimate of the true average amount of soft drink in each bottle is between 2.97 liters and 3.01 liters.
Answer:
y=5x+31
Step-by-step explanation:
y=mx+b
1=(-6*5)+b
1=-30+b
31=b
y=5x+31
(5*-6)+31
-30+31
1
you can also graph a line on desmos
Answer:
x = 5
Step-by-step explanation:
To solve this, we just have to the multiplication and do the simplification (adding up the similar terms) afterwards:
3(x+1)=7(x-2)-3 becomes...
3x + 3 = 7x - 14 - 3
3x + 3 = 7x -17
Then we move all x's on one side and all plain numbers on the other side, we'll move the x's to the right since there's a bigger value there, and will move the plain numbers on the left side, by subtracting 3x and by adding 17 on both sides
3x + 3 - 3x + 17 = 7x -17 + 17 - 3x
20 = 4x
If we isolate x alone we have:
20/4 = x or x = 5
Hey there!
Since 2 goes into 8, you would simplify. You would get 1 inch and 4 miles. Next, set up a ratio. The ratio is 1 inch: 4 miles. So for every inch on the map, there is 4 miles.
I hope this helps!
Answer:
357 / 2
Step-by-step explanation:
your answer would have been 178.5 but just a reminder always do whats in the exponets