For the given function f(t) = (2t + 1) using definition of Laplace transform the required solution is L(f(t))s = [ ( 2/s²) + ( 1/s) ].
As given in the question,
Given function is equal to :
f(t) = 2t + 1
Simplify the given function using definition of Laplace transform we have,
L(f(t))s = 
= ![\int\limits^\infty_0[2t +1] e^{-st} dt](https://tex.z-dn.net/?f=%5Cint%5Climits%5E%5Cinfty_0%5B2t%20%2B1%5D%20e%5E%7B-st%7D%20dt)
= 
= 2 L(t) + L(1)
L(1) = 
= (-1/s) ( 0 -1 )
= 1/s , ( s > 0)
2L ( t ) = 
= ![2[t\int\limits^\infty_0 e^{-st} - \int\limits^\infty_0 ({(d/dt)(t) \int\limits^\infty_0e^{-st} \, dt )dt]](https://tex.z-dn.net/?f=2%5Bt%5Cint%5Climits%5E%5Cinfty_0%20e%5E%7B-st%7D%20-%20%5Cint%5Climits%5E%5Cinfty_0%20%28%7B%28d%2Fdt%29%28t%29%20%5Cint%5Climits%5E%5Cinfty_0e%5E%7B-st%7D%20%5C%2C%20dt%20%29dt%5D)
= 2/ s²
Now ,
L(f(t))s = 2 L(t) + L(1)
= 2/ s² + 1/s
Therefore, the solution of the given function using Laplace transform the required solution is L(f(t))s = [ ( 2/s²) + ( 1/s) ].
Learn more about Laplace transform here
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Answer:
= 3f + 8
Step-by-step explanation:
Given that:
= 2/3[3f+12]+f
By simplifying:
2/3 will be multiplied inside the bracket as follows:
= 2/3*3f + 2/3*12 + f
By cancelling the terms with each other we get:
= 2f + 24/3 + f
By simplifying the fraction we get:
= 2f + 8 + f
Adding like terms
= 3f + 8
This is the simplified expression.
i hope it will help you!
That answer is x≤−8
Inequality:
8x−8≤−72
Step number 1: You have to Add 8 to both sides.
8x−8+8≤−72+8
8x≤−64
Step number 2: You have to Divide both sides by 8.
8x
/8 ≤ −64
/ 8
Ur Answer:
x≤−8
Hope this helps :)
Answer:
-66
Step-by-step explanation:
There will be $66 left after the $12 spent on lunch. 66 + -66 = 0