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kaheart [24]
3 years ago
9

6% as ratio in simplest form.

Mathematics
1 answer:
Kitty [74]3 years ago
6 0

Answer:

3 : 50

Step-by-step explanation:

6% = 0.06

0.06 = 6/100

6/100 = 3/50

3/50 = 3 : 50

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HELP ASAP
vovangra [49]

Answer:

  • See below and the attachment

Step-by-step explanation:

<em>Refer to attached graph.</em>

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4 0
3 years ago
4n - 2n = 4<br><br>what's the answer for this ?
Mademuasel [1]
Hey there!
First, we will do the subtraction with the two like terms on the left. I know they're like terms because although they have different coefficients, they have the same variable.
We have:
2n=4
Divide both sides by 3 to get:
n = 2
Hope this helps!
5 0
3 years ago
Read 2 more answers
Find the value of 5.8 divided by 1.2
Katena32 [7]
It is easier to do if we get rid of the decimals, so lets multiply both numbers by 10:
5.8/1.2 = 58/12
and reduce the fraction:
= 29/6
then operate:
= 4.83
7 0
3 years ago
1+-w2+9w and I need help cuz I’m on 76 and I’m sooo close help
Gnesinka [82]

\huge \boxed{\mathfrak{Question} \downarrow}

  • Simplify :- 1 + - w² + 9w.

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

\large \sf1 + - w ^ { 2 } + 9 w

Quadratic polynomial can be factored using the transformation \sf \: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where \sf x_{1} and x_{2} are the solutions of the quadratic equation \sf \: ax^{2}+bx+c=0.

\large \sf-w^{2}+9w+1=0

All equations of the form \sf\:ax^{2}+bx+c=0 can be solved using the quadratic formula: \sf\frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

\large \sf \: w=\frac{-9±\sqrt{9^{2}-4\left(-1\right)}}{2\left(-1\right)}  \\

Square 9.

\large \sf \: w=\frac{-9±\sqrt{81-4\left(-1\right)}}{2\left(-1\right)}  \\

Multiply -4 times -1.

\large \sf \: w=\frac{-9±\sqrt{81+4}}{2\left(-1\right)}  \\

Add 81 to 4.

\large \sf \: w=\frac{-9±\sqrt{85}}{2\left(-1\right)}  \\

Multiply 2 times -1.

\large \sf \: w=\frac{-9±\sqrt{85}}{-2}  \\

Now solve the equation \sf\:w=\frac{-9±\sqrt{85}}{-2} when ± is plus. Add -9 to \sf\sqrt{85}.

\large \sf \: w=\frac{\sqrt{85}-9}{-2}  \\

Divide -9+ \sf\sqrt{85} by -2.

\large \boxed{ \sf \: w=\frac{9-\sqrt{85}}{2}} \\

Now solve the equation \sf\:w=\frac{-9±\sqrt{85}}{-2} when ± is minus. Subtract \sf\sqrt{85} from -9.

\large \sf \: w=\frac{-\sqrt{85}-9}{-2}  \\

Divide \sf-9-\sqrt{85} by -2.

\large \boxed{ \sf \: w=\frac{\sqrt{85}+9}{2}}  \\

Factor the original expression using \sf\:ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute \sf\frac{9-\sqrt{85}}{2}for \sf\:x_{1} and \sf\frac{9+\sqrt{85}}{2} for \sf\:x_{2}.

\large \boxed{ \boxed {\mathfrak{-w^{2}+9w+1=-\left(w-\frac{9-\sqrt{85}}{2}\right)\left(w-\frac{\sqrt{85}+9}{2}\right) }}}

<h3>NOTE :-</h3>

Well, in the picture you inserted it says that it's 8th grade mathematics. So, I'm not sure if you have learned simplification with the help of biquadratic formula. So, if you want the answer simplified only according to like terms then your answer will be ⇨

\large \sf \: 1 + -  w {}^{2}  + 9w \\  =\large  \boxed{\bf \: 1 -  {w}^{2}   + 9w}

This cannot be further simplified as there are no more like terms (you can use the biquadratic formula if you've learned it.)

4 0
2 years ago
Please answer correctly
pickupchik [31]

Answer:

Graph B

Step-by-step explanation:

the "x" and "y" represent \frac{rise}{run}

so therefore, it's \frac{-2}{-2}, \frac{-1}{-1}, \frac{1}{1}, \frac{2}{2}

you would start at (0,0) or the origin

and count over one and up one, or however many units the fraction/chart tells you to count up

5 0
3 years ago
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