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4 years ago

How do you solve this using substitution? -x+y=1 x+y=-1

1 answer:

4 0

Solve for the first variable in one of the equations, then substitute the result into the other equation.
Point Form: (-1,0)
Equation form: x=-1,y=0

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4 years ago

H (t) = -t2 + t + 12 <br> Solve by using quadratic formula

Sedaia [141]

The quadratic formula is:

$x=\frac{-b+\sqrt{(b)^2-4(a)(c)}}{2a}$

and

$x=\frac{-b-\sqrt{(b)^2-4(a)(c)}}{2a}$

Let's identify our a, b, and c values:

a: -1

b: 1

c: 12

Plug in the values for a, b, and c into the equation. Let's do the first equation:

$x=\frac{-1+\sqrt{(1)^2-4(-1)(12)}}{2(-1)}$

Simplify everything in the radical:

$x=\frac{-1+\sqrt{49}}{-2}$

Simplify the radical:

$x=\frac{-1+7}{-2}$

Combine like terms:

$x=\frac{6}{-2}$

Simplify:

$x=-3$

This is one solution, now, let's solve for the other equation:

Since when simplified, everything is the same except the subtraction sign, we can skip the simplification again and change the sign to subtraction:

$x=\frac{-1-7}{-2}$

Combine like terms:

$x=\frac{-8}{-2}$

Simplify:

$x=4$

Your final answers are:

$x=-3$

$x=4$

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