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Nikolay [14]
3 years ago
9

Point C is located at (2,8). If it is reflected across the x axis, where will C be located?

Mathematics
2 answers:
salantis [7]3 years ago
7 0

Answer:

(2, -8)

Step-by-step explanation:

The answer is (2, -8) because when you reflect a point across the x-axis, the x-coordinate always remains the same, but the y-coordinate will change. In other words, the y-coordinate becomes the opposite (signs change). In this case, since the y-coordinate was positive 8, when you reflect the point across the x-axis, the y-coordinate will change to -8

ELEN [110]3 years ago
5 0
This answer is 2, -7


I think
Good luck :)
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I'll abbreviate the definite integral with the notation,

I(f(x),a,b)=\int_a^bf(x)\,\mathrm dx

We're given

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I(f,a,b)=I(f,a,c)+I(f,c,b)

The definite integral is also linear in the sense that

I(kf+\ell g,a,b)=kIf(a,b)+\ell I(g,a,b)

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Also, if a\ge b, then

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a. I(2f,1,5)=2I(f,1,5)=2(I(f,1,8)-I(f,5,8))=2(9-4)=\boxed{10}

b. I(f-g,1,8)=I(f,1,8)-I(g,1,8)=9-5=\boxed{4}

c. I(f-g,1,5)=I(f,1,5)-I(g,1,5)=\dfrac{I(2f,1,5)}2-I(g,1,5)=10-3=\boxed{7}

d. I(g-f,5,8)=I(g,5,8)-I(f,5,8)=(I(g,1,8)-I(g,1,5))-I(f,5,8)=(5-3)-4=\boxed{-2}

e. I(7g,5,8)=7I(g,5,8)=7(5-3)=\boxed{14}

f. I(3f,5,1)=3I(f,5,1)=-3I(f,1,5)=-\dfrac32I(2f,1,5)=-\dfrac32(10)=\boxed{-15}

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