<em>Hey</em><em>!</em><em>!</em><em>!</em>
<em><</em><em>a</em><em> </em><em>and</em><em> </em><em><</em><em>b</em><em> </em><em> </em><em>are</em><em> </em><em><u> </u></em><em><u>co</u></em><em><u>mpl</u></em><em><u>e</u></em><em><u>m</u></em><em><u>e</u></em><em><u>n</u></em><em><u>t</u></em><em><u>a</u></em><em><u>r</u></em><em><u>y</u></em><em><u> </u></em><em><u>angles</u></em><em><u>.</u></em>
<em><u>Those</u></em><em><u> </u></em><em><u>angles</u></em><em><u> </u></em><em><u>which</u></em><em><u> </u></em><em><u>are</u></em><em><u> </u></em><em><u>exactly</u></em><em><u> </u></em><em><u>9</u></em><em><u>0</u></em><em><u> </u></em><em><u>degree</u></em><em><u> </u></em><em><u>are</u></em><em><u> </u></em><em><u>called</u></em><em><u> </u></em><em><u>complementary</u></em><em><u> </u></em><em><u>angles</u></em><em><u>.</u></em>
<em><u>hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>helps</u></em><em><u>.</u></em><em><u>.</u></em>
Answer:
40
Step-by-step explanation:
m+25=65
65-25=40
m=40
36 bowls - since with one gallon he can eat 12 bowls (as demonstrated by 1/12), you multiply 12 by 3 to get 36 bowls.
Answer:
Z = 34
Step-by-step explanation:
From the series, we have that:
a = -2
a + d = 7
Hence, -2 + d = 7
∴ d = 7 + 2 = 9
a + 2d = X; a + 3d = Y and a + 4d = Z
-2 + 4(9) = Z
∴ Z = 36 - 2 = 34
Answer:
Second choice:


Fifth choice:


Step-by-step explanation:
Let's look at choice 1.


I'm going to subtract 1 on both sides for the first equation giving me
. I will replace the
in the second equation with this substitution from equation 1.

Expand using the distributive property and the identity
:




So this not the desired result.
Let's look at choice 2.


Solve the first equation for
by dividing both sides by 2:
.
Let's plug this into equation 2:



This is the desired result.
Choice 3:


Solve the first equation for
by adding 3 on both sides:
.
Plug into second equation:

Expanding using the distributive property and the earlier identity mentioned to expand the binomial square:



Not the desired result.
Choice 4:


I'm going to solve the bottom equation for
since I don't want to deal with square roots.
Add 3 on both sides:

Divide both sides by 2:

Plug into equation 1:

This is not the desired result because the
variable will be squared now instead of the
variable.
Choice 5:


Solve the first equation for
by subtracting 1 on both sides:
.
Plug into equation 2:

Distribute and use the binomial square identity used earlier:



.
This is the desired result.