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4 years ago

Which of the following best describes a regular polygon when the sum of its interior angles is 1260?

2 answers:

4 0

Nonagon - 9 sides

Sum of interior angle of a polygon is (n-2)180 = x

N is the number of sides, so when you plug in 1260 for x, you get 9 for n

bezimeni [28]4 years ago

4 0

Answer:

Step-by-step explanation:

Alright, lets let started.

The formula for sum of interior angle for a polygon is = $(n-2)*180$

Where n is the number of sides of polygon.

$(n-2)*180= 1260$

Dividing both sides from 180, so

$(n-2)=\frac{1260}{180}=7$

$n-2=7$

$n=9$

So, the number of sides are 9

Hence the polygon will be Nonagon. : Answer D

Hope it will help :)

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Use elimination (adding or subtracting) to find the common solution

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A) The solution (x,y) is (9,-2).

B) The solution (x,y) is (6, -1/2).

C) The solution (x,y) is (-5,2).

D) The solution (x,y) is (1, -10).

Step-by-step explanation:

A) x+y=7 and x+2y=5

Subtract the second equation from the first equation.

x+y = 7

-(x+2y = 5)

-y = 2

⇒ y = -2

The value of y is -2.

Substitute y= -2 in any of the equation.

⇒ x + (-2) = 7

⇒ x = 7+2

⇒ x = 9

The value of x is 9.

The solution (x,y) is (9,-2).

B) x+2y=5 and x-2y=7

Add both the equations.

x + 2y = 5

x - 2y = 7

2x = 12

⇒ x = 12/2

⇒ x = 6

The value of x is 6.

Substitute x= 6 in any of the equations.

⇒ 6 + 2y = 5

⇒ 2y = 5-6

⇒ 2y = -1

⇒ y = -1/2

The value of y is -1/2.

The solution (x,y) is (6, -1/2).

C) x+4y=3 and -x+y=7

Add both the equations.

x + 4y = 3

-x + y = 7

5y = 10

⇒ y = 10/5

⇒ y = 2

The value of y is 2.

Substitute y=2 in any of the equations.

⇒ -x + 2 = 7

⇒ -x = 7-2

⇒ -x = 5

⇒ x = -5

The value of x is -5.

The solution (x,y) is (-5,2).

D) 5x-2y=25 and 4x-2y=24

Subtract the second equation from the first equation.

5x - 2y = 25

- (4x - 2y = 24)

x = 1

The value of x is 1.

Substitute x=1 in any of the equations.

⇒ 5(1) - 2y = 25

⇒ 5 -2y = 25

⇒ -2y = 25-5

⇒ -2y = 20

⇒ y = -20/2

⇒ y = -10.

The value of y is -10.

The solution (x,y) is (1, -10).

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