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lions [1.4K]
3 years ago
13

A. 5y2 - 60 = 0by Square root property​

Mathematics
1 answer:
TEA [102]3 years ago
7 0

Answer:

y  = ± 2sqrt(3)

Step-by-step explanation:

5y^2 - 60 = 0

Add 60 to each side

5y^2  = 60

Divide by 5

y^2 = 60/5

y^2 = 12

Take the square root of each side

sqrt( y^2) = ± sqrt(12)

y = ± sqrt(4*3)

y =  ±sqrt(4) sqrt(3)

y  = ± 2sqrt(3)

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Answer:

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Step-by-step explanation:

8 0
3 years ago
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If -1 is one of the zeroes of py 3x^3-5x^2-11x-3 find other zeroes
katrin2010 [14]

Given:

The function is:

y=3x^3-5x^2-11x-3

It is given that -1 is a zero of the given function.

To find:

The other zeroes of the given function.

Solution:

If c is a zero of a polynomial P(x), then (x-c) is a factor of the polynomial.

It is given that -1 is a zero of the given function. So, (x+1) is a factor of the given function.

We have,

y=3x^3-5x^2-11x-3

Split the middle terms in such a way so that we get (x+1) as a factor.

y=3x^3+3x^2-8x^2-8x-3x-3

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Again splitting the middle term, we get

y=(x+1)(3x^2-9x+x-3)

y=(x+1)(3x(x-3)+1(x-3))

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For zeroes, y=0.

(x+1)(3x+1)(x-3)=0

(x+1)=0 and 3x+1=0 and x-3=0

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3 0
2 years ago
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13 + 1
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Hope this helps!
8 0
3 years ago
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solve. PEMDAS
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Multiplication & Division second (left to right)
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