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4 years ago

Find the equation of the linear function represented by the table below in

Mathematics

1 answer:

d1i1m1o1n [39]4 years ago

4 0

1/3 is da answer I may be wrong

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Let X be a Bernoulli rv with pmf as in Example 3.18. a. Compute E(X2 ). b. Show that V(X) 5 p(1 2 p). c. Compute E(X79).

spayn [35]

The Bernoulli distribution is a distribution whose random variable can only take 0 or 1

The value of E(x2) is p
The value of V(x) is p(1 - p)
The value of E(x79) is p

<h3>How to compute E(x2)</h3>

The distribution is given as:

p(0) = 1 - p

p(1) = p

The expected value of x2, E(x2) is calculated as:

$E(x^2) = \sum x^2 * P(x)$

So, we have:

$E(x^2) = 0^2 * (1- p) + 1^2 * p$

Evaluate the exponents

$E(x^2) = 0 * (1- p) + 1 * p$

Multiply

$E(x^2) = 0 +p$

Add

$E(x^2) = p$

Hence, the value of E(x2) is p

<h3>How to compute V(x)</h3>

This is calculated as:

$V(x) = E(x^2) - (E(x))^2$

Start by calculating E(x) using:

$E(x) = \sum x * P(x)$

So, we have:

$E(x) = 0 * (1- p) + 1 * p$

$E(x) = p$

Recall that:

$V(x) = E(x^2) - (E(x))^2$

So, we have:

$V(x) = p - p^2$

Factor out p

$V(x) = p(1 - p)$

Hence, the value of V(x) is p(1 - p)

<h3>How to compute E(x79)</h3>

The expected value of x79, E(x79) is calculated as:

$E(x^{79}) = \sum x^{79} * P(x)$

So, we have:

$E(x^{79}) = 0^{79} * (1- p) + 1^{79} * p$

Evaluate the exponents

$E(x^{79}) = 0 * (1- p) + 1 * p$

Multiply

$E(x^{79}) = 0 + p$

Add

$E(x^{79}) = p$

Hence, the value of E(x79) is p

Read more about probability distribution at:

brainly.com/question/15246027

5 0

3 years ago

Kathleen makes bracelets to sell in a booth at a local store. She spent $62.30 on supplies to make bracelets for the next month.

vodomira [7]

Answer:

$105.20

Step-by-step explanation:

Given that :

Cost of materials = $62.30

Cost of booth = $25 / month

Price per bracelet = $5.50

Profit of 35 bracelet is sold next month =?

Profit = Revenue - Expenses

Revenue = $5.50 * 35 = $192.50

Expenses = $25 + $62.30 = $87.30

Profit = $192.50 - $87.30

= $105.20

4 0

3 years ago

Which simplified fraction is equal to 0.53 repeating?

GalinKa [24]

Answer: I believe its 5/9

Step-by-step explanation:

As you can see, the only fraction that doesn't equal 0.53, or the outlier, is 5/9 or 0.5556

5 0

3 years ago

Ruby uses 1/4 yard of ribbon to make 2 bows.Which expression shows the length of ribbon in each bow?

allochka39001 [22]

What you can do in this case is a rule of three to determine the length of each bow.
We have then:
1/4 ---> 2
x ------> 1
Clearing x we have:
x = (1/2) * (1/4)
x = 1/8
Answer:
the length of ribbon in each bow is
x = 1/8
Equivalently:
x = (1/4) / 2
Option 3

3 0

3 years ago

Towns Kand L are shown on a map.

Rom4ik [11]

I’m not sure but is it C?

4 0

2 years ago