The molar enthalpy is 447 kJ and the reaction is endothermic
You would need to isolate the variable by dividing each side by factors that don't contain the variable. So, the answer would be
x = 2.2
Answer:
16.68 m/s
Explanation:
The following data were obtained from the question:
Height (h) = 14.2 m
Initial Velocity (u) = 0 m/s
Final velocity (v) =?
Thus, the velocity (v) with which the ball hit the ground can be obtained as follow:
v² = u² + 2gh
NOTE: the acceleration due to gravity (g) = 9.8 m/s²
v² = u² + 2gh
v² = 0² + 2 × 9.8 × 14.2
v² = 0 + 278.32
v² = 278.32
Take the square root of both side
v = √278.32
v = 16.68 m/s
Therefore, the velocity with which the ball hit the ground is 16.68 m/s