Explanation:
The given data is as follows.
= 225.5 mL, 
= 45.00 mL
= 0.09988 M, 
= ?
Therefore, formula to calculate final concentration will be as follows.
= 
Putting the given values into the above formula as follows.
=
= 
= 0.5 M
Thus, we can conclude that the final concentration of the given solution is 0.5 M.
Answer:
6.25%
Explanation:
Given data:
Half life of lutetium-117 = 6.75 days
Percentage remaining after 27 days = ?
Solution;
Number of half lives = Time elapsed / half life
Number of half lives = 27 days / 6.75 days
Number of half lives = 4
At time zero = 100%
At first half life = 100%/2 = 50%
At second half life = 50%/2 = 25%
At 3rd half life = 25%/2 = 12.5%
At 4th half life = 12.5%/2 = 6.25%
<h2>Project Reports</h2>
<h3>A) Mixture</h3>
This refers to the material that is made when different substances mix up physically and causes a reaction.
You can make on the project of Mixture -
- 1) Alloys
- 2)Colloids
- 3) Suspension
- 4) Solution
<h3>B) Compound</h3>
This refers to the chemical bond that holds different atoms tightly
You can make on the project of Compound -
- 1)Water
- 2)Methane
- 3)Carbon Dioxide
- 4) Sulfuric Acid
<h3>C) Elements</h3>
Based on the fact that the atom is the smallest indivisible part of an element, elements like phosphorous cannot be further broken down.
You can make on the project of Elements -
- 1) Mercury
- 2) Iron
- 3) Copper
- 4)Carbon
Read more about mixtures and compounds here:
brainly.com/question/491220
#SPJ1
Thermal expansion<span> is the tendency of matter to change in shape, area, and volume in response to a change in temperature, through heat transfer. Temperature is a monotonic function of the average molecular kinetic energy of a substance. When a substance is heated, the kinetic energy of its molecules increases.</span>
<span>C2H5
First, you need to figure out the relative ratios of moles of carbon and hydrogen. You do this by first looking up the atomic weight of carbon, hydrogen, and oxygen. Then you use those atomic weights to calculate the molar masses of H2O and CO2.
Carbon = 12.0107
Hydrogen = 1.00794
Oxygen = 15.999
Molar mass of H2O = 2 * 1.00794 + 15.999 = 18.01488
Molar mass of CO2 = 12.0107 + 2 * 15.999 = 44.0087
Now using the calculated molar masses, determine how many moles of each product was generated. You do this by dividing the given mass by the molar mass.
moles H2O = 11.5 g / 18.01488 g/mole = 0.638361 moles
moles CO2 = 22.4 g / 44.0087 g/mole = 0.50899 moles
The number of moles of carbon is the same as the number of moles of CO2 since there's just 1 carbon atom per CO2 molecule.
Since there's 2 hydrogen atoms per molecule of H2O, you need to multiply the number of moles of H2O by 2 to get the number of moles of hydrogen.
moles C = 0.50899
moles H = 0.638361 * 2 = 1.276722
We can double check our math by multiplying the calculated number of moles of carbon and hydrogen by their respective atomic weights and see if we get the original mass of the hydrocarbon.
total mass = 0.50899 * 12.0107 + 1.276722 * 1.00794 = 7.400185
7.400185 is more than close enough to 7.40 given rounding errors, so the double check worked.
Now to find the empirical formula we need to find a ratio of small integers that comes close to the ratio of moles of carbon and hydrogen.
0.50899 / 1.276722 = 0.398669
0.398669 is extremely close to 4/10, so let's reduce that ratio by dividing both top and bottom by 2 giving 2/5.
Since the number of moles of carbon was on top, that ratio implies that the empirical formula for this unknown hydrocarbon is
C2H5</span>
