Balance the following chemical equations

Which component is required for the activation of some enzymes?

shepuryov [24]

The best answer is letter A.
The main factors that change the speed of enzymatic reactions are temperature, pH and substrate concentration (quantity). <span>There are enzymes that need other associated molecules to work. These molecules are called enzyme co-factors. They can be organic ions like mineral salts.</span>

5 0

3 years ago

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One beaker contains 100 mL of pure water and second beaker contains 100 mL of seawater. The two beakers are left side by side on

gayaneshka [121]

Explanation:

When we add a non-volatile solute in a solvent then due to the impurity added to the solution there will occur an increase in the boiling point of the solution.

This increase in boiling point will be known as elevation in boiling point.

As one beaker contains seawater (water having NaCl) will have some impurity in it. So, more temperature is required by seawater to escape into the atmosphere.

Whereas another beaker has only pure water so it is able to easily escape into the atmosphere since, it contains no impurity.

Thus, we can conclude that level of pure water will decrease more due to non-volatile solute present in it as compared to seawater.

7 0

3 years ago

An element is any substance that cannot be broken down into simpler substances. The smallest unit of an element is called an ___

Svetradugi [14.3K]

Answer:

An Atom

Explanation:

An atom is the smallest unit of matter

3 0

3 years ago

A flash distillation chamber operating at 101.3 kpa is separating an ethanol water mixture the feed mixture contains z weight et

Alex73 [517]

Answer:

The answer is $[\frac{LX_1}{46} + \frac{L(1-x)}{18}]\times0.454$ mol/hr

$[\frac{Vy_1}{46}+\frac{V(1-y)}{18}]\times0.454$ mol/hr

Explanation:

For flash distillation

F = V+L

$\frac{V}{F} + \frac{L}{F} = 1$

$\frac{F}{V} -\frac{L}{V} = 1$

Fz = Vy+Lx

Y = $\frac{F}{V}\times Z - \frac{L}{V}\times X$ let, $\frac{V}{F} = F$

$y = \frac{Z}{F} -[ \frac{1}{F} -1]\times X$

Highlighted reading

F = 299; $\frac{V}{F}$ = 0.85 ; z = 0.36

y = $\frac{0.36}{0.85} - (-0.15)\times X$

= 0.423 + 0.15x ------------(i)

$y^{*}$ = -43.99713 $x^{6}$ + 148.27274 $x^{5}$ - 195.46 $x^{4}$ +127.99 $x^{3}$ -43.3 $x^{2}$ + 7.469 $x^{}$ + 0.02011

At equilibrium, $y^{*}$ = y

0.423+0.15 $x^{}$ = $y^{*}$

-43.99713 $x^{6}$ + 148.27274 $x^{5}$ - 195.46 $x^{4}$ +127.99 $x^{3}$ -43.3 $x^{2}$ + 7.319 $x^{}$ -0.403

F(x) for Newton's Law

Let $x_{0} = 0$

$x_{1}$ = $\frac{0-[{-0.403}]}{7.319}$

= 0.055

$x_{2}$ = $\frac{{0.055}-{f(0.055)} {{{{{{{}}}}}}}}{f^{'} (0.055)}$

= $\frac{{(0.055)}-(-0.11)}{3.59}$

= 0.085

$x^{3}$ = $\frac{{0.085}-(0.024)}{2.289}$

= 0.095

$x^{4}$ = $\frac{{0.095}-(-0.0353)}{-1.410}$

= 0.07

From This x and y are found from equation (i) and L and V are obtained from $\frac{V}{F}$ and F values

$[\frac{LX_1}{46} + \frac{L(1-x)}{18}]\times0.454$ mol/hr

$[\frac{Vy_1}{46}+\frac{V(1-y)}{18}]\times0.454$ mol/hr

8 0

3 years ago

in diagram of the heart, the right side is colored blue to indicate its low in oxygen and high in ____________

marissa [1.9K]

Answer:

<h2>CO2 (Carbon dioxide)</h2>

Explanation:

The right side is collored blue to indicate that the blood pumping through here is low on oxygen, but high in carbon dioxide. Because the blood is so low on oxygen, and high in carbon dioxide (a byproduct of Cellular Respiration), the blood will be pumped to the lungs where the CO2 is removed, and oxygen is taken in.

7 0

2 years ago

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