All categories

3 years ago

Which of the following would be part of an aquatic ecosystem?

Chemistry

2 answers:

german3 years ago

4 0

Answer: All of the given choices.

Explanation:

The ecosystem can be defined as the combination of the biotic and abiotic factors. The biotic factors consists of the living systems and the abiotic factors consists of the non living parts of the ecosystem.

The biotic part of the aquatic ecosystem is sponges and plankton. This is because they are living.

The abiotic part of the aquatic system consists of amount of sunlight ad temperature of water because they are non living.

Masja [62]3 years ago

3 0

Answer:

Aquatic ecosystem has two components -

Biotic components

2.Abiotic components

temperature and amount of sunlight are the part of abiotic component .

while living things like sponges and planktons are the biotic components of ecosystem.

Explanation:

aquatic components are of two types-

freshwater ecosystem( lakes and ponds, river and streams)

marine ecosystem(ocean ecosysyem, estuaries)

planktons-

planktons are found in limnetic zone, availability of sunlight is much here. planktons are zooplanktons and phytoplanktons are very important link in aquatic ecosystem.

sponges

In marine water, the benthic zone is the area below the pelagic zone. Here temperature decreased because of less light perception. This zone is very nutrient rich so organisms which are present here are- bacteria, fungi, sea anemone, sponges and some fishes.

You might be interested in

Calculate the average bond order for a p−o bond (such as the one shown in blue) in a phosphate ion. express your answer numerica

PtichkaEL [24]

Answer: 1/4 is the average bond order for a pâ’o bond (such as the one shown in blue) in a phosphate ion.

5 0

3 years ago

The Law of Superposition states

lora16 [44]

In an undisturbed sequence of layers of rocks, the younger layers lie on top of the older layers

8 0

3 years ago

When a hydrogen atom makes the transition from the second excited state to the ground state (at -13.6 eV) the energy of the phot

viktelen [127]

Answer : The energy of the photon emitted is, -12.1 eV

Explanation :

First we have to calculate the $'n^{th}'$ orbit of hydrogen atom.

Formula used :

$E_n=-13.6\times \frac{Z^2}{n^2}ev$

where,

$E_n$ = energy of $n^{th}$ orbit

n = number of orbit

Z = atomic number of hydrogen atom = 1

Energy of n = 1 in an hydrogen atom:

$E_1=-13.6\times \frac{1^2}{1^2}eV=-13.6eV$

Energy of n = 2 in an hydrogen atom:

$E_3=-13.6\times \frac{1^2}{3^2}eV=-1.51eV$

Energy change transition from n = 1 to n = 3 occurs.

Let energy change be E.

$E=E_-E_3=(-13.6eV)-(-1.51eV)=-12.1eV$

The negative sign indicates that energy of the photon emitted.

Thus, the energy of the photon emitted is, -12.1 eV

3 0

3 years ago

Write the balanced chemical equation between H2SO4 and KOH in aqueous solution. This is called a neutralization reaction and wil

emmainna [20.7K]

Answer:

0.166M

Explanation:

In a neutralization, the acid, H₂SO₄, reacts with a base, KOH, to produce a salt, K₂SO₄ and water. The reaction is:

H₂SO₄ + 2KOH → K₂SO₄ + 2H₂O

To solve this problem, we need to determine moles of H2SO4 and moles of KOH that reacts to find the moles of sulfuric acid that remains after the reaction:

Moles H2SO4:

0.650L * (0.430mol /L) = 0.2795moles H2SO4

Moles KOH:

0.600L * (0.240mol / L) = 0.144 moles KOH

Moles of sulfuric acid that reacts with 0.144 moles of KOH are:

0.144 moles KOH * (1mol H2SO4 / 2 mol KOH) = 0.072 moles of H2SO4 react.

And remain:

0.2795moles H2SO4 - 0.072moles H2SO4 = 0.2075 moles of H2SO4 reamains.

In 0.650L + 0.600L = 1.25L:

Molar concentration of sulfuric acid:

0.2075 moles of H2SO4 / 1.25L =

7 0

2 years ago

What parts of a wave are used to determine the wavelength of that wave

Ann [662]

The trough and the hill part

7 0

3 years ago