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crimeas [40]
4 years ago
5

Help find the value of x

Mathematics
2 answers:
Lina20 [59]4 years ago
6 0

Answer:

40

Step-by-step explanation:

Arlecino [84]4 years ago
3 0

Answer:

Step-by-step explanation:

Wow thats hard.  it says 17, right?

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Find the solution(s) for x in the equation below.
Kobotan [32]

Answer:

D) x=5, x=-5.

Step-by-step explanation:

x^2-25=0

factor

(x+5)(x-5)=0

x+5=0, x-5=0,

x=0-5=-5,

x=0+5=5.

5 0
3 years ago
Find the values of m and b for this line.
Andrej [43]

Answer:

b=-5, m= - 3/-2

Step-by-step explanation:

Slope equation is y=mx+b. Slope is finding the rise(vertical change) over run(horizontal change). In this case, -3 is our negative rise and 2 is our run. Put that into fraction form, we get negative 3/2. In the slope equation, b represents the y-intercept(where the line touches the y-axis). In this case, it is -5. Hope this helps you!

6 0
2 years ago
Ldentify the following sections of the textbook.
Tema [17]
I don’t know what the drop down options are so I can’t answer your question. Sorry but can u pls help answer my question I just posted? That would be very helpful thx!
7 0
3 years ago
The figure shows △ABC . BD is the angle bisector of ∠ABC .
Misha Larkins [42]
From angle bisector theorem, we know that:

\dfrac{|AD|}{|DC|}=\dfrac{|BA|}{|BC|}\\\\\\\dfrac{|AD|}{|DC|}=\dfrac{8}{10}=\dfrac{4}{5}

Moreover:

|AD|+|DC|=6

so:

|DC|=6-|AD|

and

\dfrac{|AD|}{|DC|}=\dfrac{4}{5}\\\\\\\dfrac{|AD|}{6-|AD|}=\dfrac{4}{5}\qquad\qquad\text{cross multiplying}\\\\\\ 5\cdot|AD|=4\cdot\big(6-|AD|\big)\\\\5\cdot|AD|=24-4\cdot|AD|\\\\5\cdot|AD|+4\cdot|AD|=24\\\\9\cdot|AD|=24\qquad|:9\\\\\\|AD|=\dfrac{24}{9}=\boxed{\dfrac{8}{3}}

3 0
3 years ago
Read 2 more answers
Given that triangle ABC is a right triangle, select a set of possible side length measures.
ad-work [718]

You didn't supply any rules or constraints so.... 1 in., 1 in., and 1 in.

You can use the Pythagorean Theorem to check if the side lengths are appropriate.

a^2 + b^2 = c^2

1^2 + 1^2 = 1^2 –this is true.

5 0
4 years ago
Read 2 more answers
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