All categories

3 years ago

A line has a zero slope and

1 answer:

3 0

Hello here is a solution :
equation for the line is : y = ax+b a : slope
a = 0
passes through the point (-5, 4) : 4 =0(-5)+b
b= 4
equation for the line is : y =4

You might be interested in

Evaluate the following expression.<br> 1/5^-2

Romashka [77]

This is how the whole equation goes:
1/x^-a = x^a
So, 1/5^-2 is the same as 5^2, which is 25.

8 0

2 years ago

Read 2 more answers

The length of a rectangular flower bed is 2ft longer than the width. If the area is 6ft, then what are the exact length and widt

Marizza181 [45]

Answer:

Exact dimensions:

$width=-1+\sqrt{7}$

$length=-1+\sqrt{7}+2$

$length=1+\sqrt{7}$

Approximate dimensions:

$width=1.64575ft$

$length=1.64575+2$

$length=3.64575ft$

Step-by-step explanation:

Let's assume width of rectangle is w ft

The length of a rectangular flower bed is 2ft longer than the width

so,

length =w+2

$L=w+2$

now, we can find area

$A=L\times W$

now, we can plug it

$A=(w+2)\times w$

$A=w^2+2w$

we are given area =6

so, we can set it equal

and then we can solve for w

$w^2+2w=6$

$w^2+2w-6=0$

we can use quadratic formula

$ax^2+bx+c=0$

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

now, we can compare and find a,b and c

a=1 , b=2 , c=-6

$w=\frac{-2\pm \sqrt{2^2-4\cdot \:1\left(-6\right)}}{2\cdot \:1}$

$w=-1+\sqrt{7},\:w=-1-\sqrt{7}$

we know that dimension can never be negative

so, we will only consider positive value

Exact dimensions:

$width=-1+\sqrt{7}$

$length=-1+\sqrt{7}+2$

$length=1+\sqrt{7}$

Approximate dimensions:

$width=1.64575ft$

$length=1.64575+2$

$length=3.64575ft$

7 0

3 years ago

A deposit of $7,500 is made into a savings account which earns 5

melisa1 [442]

Thats easy the answer is b

8 0

3 years ago

Read 2 more answers

What are the domain and range of this function?

RUDIKE [14]

<h3>Answer: Choice D</h3>

Domain: all real numbers
Range: $y \ge 1$

===========================================

Explanation:

The domain is the set of allowed x inputs. We can plug in any x value we want as the graph stretches on forever to the left and to the right. There aren't any division by zero errors or any issues like that to worry about, so that's why we don't kick out any x values from the domain.

The domain being all real numbers translates to the interval notation $(-\infty, \infty)$ which is basically saying $-\infty < x < \infty$