Answer:
You can verify if lines are parallel if they have the same slope and different y-intercepts and if they don't intersect each other. You can also graph the 2 equations to see if they ever intersect.
Step-by-step explanation:
Answer:
what do you mean also working out to a better grade and working out better at math
Step-by-step explanation:
Answer:
direct relation between distance travelled by a train and its speed, when time is constant.
Step-by-step explanation:
We know that the speed of an object is the total distance covered divided by total time taken. Mathematically, it is given by :
![v=\dfrac{d}{t}](https://tex.z-dn.net/?f=v%3D%5Cdfrac%7Bd%7D%7Bt%7D)
Where
d is distance
t is time taken
It can be seen that relation between the distance and the speed is direction. Hence the correct option is (a) "direct".
I thought I saw this one earlier and there were people answering. Guess not.
h(t) = 5 + 98t - 4.9t²
h(0) = 5 meters
h(5) = 5 + 98(5) - 4.9(5)² = 372.5 meters
h(10) = 5 + 98(10) - 4.9(10)² = 5 + 980 - 490 = 495 meters
h(15) = 5 + 98(15) - 4.9(15²) = 372.5 meters
h(20) = 5 meters
I'll leave the graphing to you, plot those points
(0,5), (5,372,5),(10,495),(15,372.5) (20,5)
and connect the dots
It's coming down pretty fast at 5 feet up 20 seconds. That last bit is 5/495 or 1% of the trip, so probably double the average speed of around 50m/s so 100msec or .05 sec to go 5 meters.
So it's in the ground at about 20.05 seconds after launch.
Answer: 20.05 meters
I’m pretty sure the answer is -1