The water level increases by 0.608 meters per minute when the water is 3.5 m deep
<h3>How to determine the rate?</h3>
The given parameters are:
- Radius, r = 3
- Height, h = 7
- Rate in, V' = 4.3m^3/min
The relationship between the radius and height is:
r/h = 3/7
Make r the subject
r = 3h/7
The volume of a cone is;
![V = \frac 13\pi r^2h](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%2013%5Cpi%20r%5E2h)
This gives
![V = \frac 13\pi (\frac{3h}{7})^2h](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%2013%5Cpi%20%28%5Cfrac%7B3h%7D%7B7%7D%29%5E2h)
Expand
![V = \frac{3h^3}{49}\pi](https://tex.z-dn.net/?f=V%20%3D%20%20%5Cfrac%7B3h%5E3%7D%7B49%7D%5Cpi)
Differentiate
![V' = \frac{9h^2}{49}\pi h'](https://tex.z-dn.net/?f=V%27%20%3D%20%5Cfrac%7B9h%5E2%7D%7B49%7D%5Cpi%20h%27)
Make h' the subject
![h' = \frac{49}{9\pi h^2}V'](https://tex.z-dn.net/?f=h%27%20%3D%20%5Cfrac%7B49%7D%7B9%5Cpi%20h%5E2%7DV%27)
When the water level is 3.5.
We have:
![h' = \frac{49}{9\pi * 3.5^2}V'](https://tex.z-dn.net/?f=h%27%20%3D%20%5Cfrac%7B49%7D%7B9%5Cpi%20%2A%203.5%5E2%7DV%27)
Also, we have:
V' = 4.3
So, the equation becomes
![h' = \frac{49}{9\pi * 3.5^2} * 4.3](https://tex.z-dn.net/?f=h%27%20%3D%20%5Cfrac%7B49%7D%7B9%5Cpi%20%2A%203.5%5E2%7D%20%2A%204.3)
Evaluate the products
![h' = \frac{210.7}{346.36}](https://tex.z-dn.net/?f=h%27%20%3D%20%5Cfrac%7B210.7%7D%7B346.36%7D)
Evaluate the quotient
h' = 0.608
Hence, the water level increases by 0.608 meters per minute
Read more about volumes at:
brainly.com/question/10373132
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Answer:
disagree
Step-by-step explanation:
toa=opposit over adjacent= 12/9
tan(x)=12/9
tan^-1=12/9
x= 53.1
Answer:
696 large bags of flour were packed.
Step-by-step explanation:
Let large bags of flour be 'y'
Let small bags of flour be 'x'. That is x=2040 (according to the question)
![(3 \times x) + (5 \times y) = 9600](https://tex.z-dn.net/?f=%283%20%5Ctimes%20x%29%20%2B%20%285%20%5Ctimes%20y%29%20%3D%209600)
![(3 \times 2040) + ( 5 \times y) = 9600](https://tex.z-dn.net/?f=%283%20%5Ctimes%202040%29%20%2B%20%28%205%20%5Ctimes%20y%29%20%3D%209600)
![(6120) + (5 \times x) = 9600](https://tex.z-dn.net/?f=%286120%29%20%2B%20%285%20%5Ctimes%20x%29%20%3D%209600)
![(5 \times x) = 9600 - 6120](https://tex.z-dn.net/?f=%285%20%5Ctimes%20x%29%20%3D%209600%20-%206120)
![(5 \times x) = 3480](https://tex.z-dn.net/?f=%285%20%5Ctimes%20x%29%20%3D%203480)
![x = 3480 \div 5](https://tex.z-dn.net/?f=x%20%3D%203480%20%20%5Cdiv%205)
![x = 696](https://tex.z-dn.net/?f=x%20%3D%20696)
HOPE IT HELPS
#PEACE
Answer:
point symmetry if no symmetry isn't an option as it looks grayed out and not clickable
Answer:
You need to carry the one over by subtracting 1 from 33. The new equation will be 18n = 32