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Bezzdna [24]
3 years ago
9

Help me quickkkk please

Mathematics
1 answer:
Maurinko [17]3 years ago
5 0

Answer:

with? i dont see any pic

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I REALLY NEED HELP LIKE ASAP
Akimi4 [234]

1. The square on the inside is 8 x 8 = 64

2. The triangle's area is 8x9x1/2= 72 x 1/2 = 36

3. there are 4 triangles so 36 x 4 = (or 72 x 2 ) = 144 :)

7 0
3 years ago
Read 2 more answers
The value of C has to be Greater than 0.65
grin007 [14]

Answer:

1.3

Step-by-step explanation:

1. .65 = .5c ---> .65/.5

2. 1.3 = c

4 0
3 years ago
Help me please help me ASAP please please
Arturiano [62]

Answer:

put 0 first

Step-by-step explanation:

4 0
3 years ago
Which of the following are the coordinates of the vertex of y = −x2 + 2x + 1? (2, 1) (1, –2) (1, 2) (–2, 1)
IceJOKER [234]

Answer:

C

Step-by-step explanation:

We want to determine the vertex of the quadratic equation:

\displaystyle y = -x^2 + 2x + 1

Recall that the vertex is given by the formulas:

\displaystyle \text{Vertex} = \left(-\frac{b}{2a}, f\left(-\frac{b}{2a}\right)\right)

In this case, <em>a</em> = -1, <em>b</em> = 2, and <em>c</em> = 1.

Determine the <em>x-</em>coordinate of the vertex:

\displaystyle x = -\frac{(2)}{2(-1)} = 1

To determine the <em>y-</em>coordinate, evaluate the function at <em>x</em> = 1:

\displaystyle \begin{aligned} y(1)&= -(1)^2 + 2(1) + 1 \\ &= 2\end{aligned}

In conclusion, the vertex of the quadratic equation is (1, 2).

Hence, our answer is C.

3 0
2 years ago
Y=-1/3x^2-4x-5 in vertex form
grigory [225]

Answer:

Y=-\frac{1}{3}(x+6)^2+7   [Vertex form]

Step-by-step explanation:

Given function:

Y=-\frac{1}{3}x^2-4x-5

We need to find the vertex form which is.,

y=a(x-h)^2+k

where (h,k) represents the co-ordinates of vertex.

We apply completing square method to do so.

We have  

Y=-\frac{1}{3}x^2-4x-5

First of all we make sure that the leading co-efficient is =1.

In order to make the leading co-efficient is =1, we multiply each term with -3.

-3\times Y=-3\times\frac{1}{3}x^2-(-3)\times4x-(-3)\times 5

-3Y=x^2+12x+15

Isolating x^2 and x terms on one side.

Subtracting both sides by 15.

-3Y-15=x^2+12x-15-15

-3Y-15=x^2+12x

In order to make the right side a perfect square trinomial, we will take half of the co-efficient of x term, square it and add it both sides side.  

square of half of the co-efficient of x term = (\frac{1}{2}\times 12)^2=(6)^2=36

Adding 36 to both sides.

-3Y-15+36=x^2+12x+36

-3Y+21=x^2+12x+36

Since x^2+12x+36 is a perfect square of (x+6), so, we can write as:

-3Y+21=(x+6)^2

Subtracting 21 to both sides:

-3Y+21-21=(x+6)^2-21

-3Y=(x+6)^2-21

Dividing both sides by -3.

\frac{-3Y}{-3}=\frac{(x+6)^2}{-3}-\frac{21}{-3}

Y=-\frac{1}{3}(x+6)^2+7   [Vertex form]

8 0
3 years ago
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